That would be a quadratic expression which describes a parabola. You can find where it intersects the x-axis by solving it for zero:
x2 + 2x - 7 = 0
x2 + 2x + 1 = 8
(x + 1)2 = 8
x + 1 = ± 2√2
x = -1 ± 2√2
This tells us that it intersects the x-axis at the points where x equals -1 + 2√2 and -1 - 2√2.
If you'd like to find it's vertex, you can check that easily by taking it's derivative with respect to x and solving that for zero:
y = x2 + 2x - 7
y' = 2x + 2
Let y' = 0:
0 = 2x + 2
2x = -2
x = -1
So we know that the vertex of this parabola is at the point where x = -1.
x2+1/4x = 0 x(x+1/4) = 0 Therefore: x = 0 or x = -1/4
Yes because if 1+0=1 than 0 plus b equals b
(x + 1)(x - 15) gives roots of -1 and 15, and a = 14; (x + 5)(x - 3) gives roots of -5 and 3, and a = 2.
x = y = 0 ?
many solutions
(x-2)(x-4) x=2,4 ans
x2+1/4x = 0 x(x+1/4) = 0 Therefore: x = 0 or x = -1/4
x2+7x+12=0usually this means to factor the equation.factored this equation would be...(x+3)(x+4)
I'm going to assume the polynomial in question is 2x7+(3-2x3)+(5x8-4x) Expanding out the polynomial: 2x7+3-2x3+5x8-4x Order the terms by powers of x: 5x8+2x7-2x3-4x+3 Since 8 is the highest power of x, the degree of the polynomial is 8.
If you are solving for x, x2 - 2x + 1 = 0 Factor: (x-1)(x-1) = 0 Therefore: (x - 1)2 = 0 (x - 1) = 0 x = 1
Yes because if 1+0=1 than 0 plus b equals b
The equation you are looking for is x + 5 = 0. To solve for x, you would subtract 5 from both sides of the equation. This would give you x = -5. Therefore, -5 plus 5 equals 0.
A=0 b=0 c=0
(x + 1)(x - 15) gives roots of -1 and 15, and a = 14; (x + 5)(x - 3) gives roots of -5 and 3, and a = 2.
No.
x = y = 0 ?
many solutions