Because it takes 2a to make 1mol of a2b, the ratio is 1mol a2b/2mol a. If you only have 1.0 mol of a to react, then 1mol a x (1mol a2b/2 mol a)= 0.5 mol of a2b Because it takes 1 mol of b to make 1 mole of a2b, the ratio is 1mol a2b/1mol b. So, 1.0 mol b x (1mol a2b/1mol b)= 1.0 mol of a2b. Since you run out of a to react with b, a is the limiting reagent meaning that you can only produce 0.5 mol of a2b even though you have an excess amount of b. So, only 0.5 mol of a2b can be produced.
The GCF is a2b
It is a2b.
7
that equals 2*2*2 which equals eight
it's something 4 sure!
Because it takes 2a to make 1mol of a2b, the ratio is 1mol a2b/2mol a. If you only have 1.0 mol of a to react, then 1mol a x (1mol a2b/2 mol a)= 0.5 mol of a2b Because it takes 1 mol of b to make 1 mole of a2b, the ratio is 1mol a2b/1mol b. So, 1.0 mol b x (1mol a2b/1mol b)= 1.0 mol of a2b. Since you run out of a to react with b, a is the limiting reagent meaning that you can only produce 0.5 mol of a2b even though you have an excess amount of b. So, only 0.5 mol of a2b can be produced.
The GCF is a2b.
If you mean 2a8b - 5 = x and a2b = 5, then: 2(54) - 5 = x x = 1350 - 5 x = 1345
(a2 + 2)(b + 3)
my blood group is A2B +ve .. in under what blood group it comes ??
The cast of a2b - 2005 includes: Guy Lockhart as Adam Budding
The GCF is a2b
(a -b) · (a2+ab+b2) = (a3+a2b+ab2) - (a2b+ab2+b3) = a3 -b3 (a+b) · (a2 -ab+b2) = (a3 -a2b+ab2) +(a2b -ab2+b3) = a3+b3 More generally: (a ∓ b) · (an-1 ±an-2b +an-3b2 ±an-4b3 +±...+a(±b)n-2 +(±b)n-1) = an ± bn. The mixed terms cancel out themselves.
a2b.<---answer.
yes
200a2bc