Pls.answer me of above question
To calculate the amperage in a 15kVA circuit at 440 volts, you can use the formula: Amperage = Power (kVA) / Voltage (V) * 1000. Plugging in the values, you get: Amperage = 15 / 440 * 1000 ≈ 34.09 amps.
On an average load on a 15 kc DG is about 4 littered of diesel per hour.
Generator will not run or miss very badly. Drain all the fuel out and drain the lines. Replace the fuel filter and fill it up with Diesel.
might be interested in having a look at this: Single-phase power through three-phase self-excited induction generator utilizing renewable energy resources by Goel, SK (Goel, Sandeep Kumar); Srivastava, A (Srivastava, Ajay) search for it online Regards, Bill
To convert horsepower (hp) to kilovolt-amperes (kVA), you can use the formula kVA = hp x 0.746. Therefore, for a 12hp motor, the kVA rating would be approximately 8.95 kVA.
A 20 hp piston motor compressor at 208/230v appx. 50 amp running, and 100 amp locked rotor current, requiring 70 amp heaters. A rotary screw will demand apprx. 20% greater locked rotor, but about the same running, and perhaps 80 amp heaters. Halve most all for 460/480v. A 12 - 15kva generator should suffice. If the budget will sustain, go for a 25kva.
In theory, you should be able to load your generator to 15 kV.A (mine stalls far below that load, though!!!). So, divide this figure by the rated output voltage of the generator, and this tells you the maximum current it can supply. The sum of your individual loads should not exceed that value of current. (The current drawn by an individual load is its power rating divided by the supply voltage -just add them up!).
A volt ampere (symbol: V.A) is the unit of measurement for the apparent power of a load connected to an AC supply. Apparent power is the product of the supply voltage and the load current. Apparent power is the vector sum of a load's true power (measured in watts) and reactive power(measured in reactive volt amperes). '15 kV.A', means 15 000 V.A.Further explanationIn the descriptive name "kVA", k = 1000 and VA = volt.amperes.Volts x amps = volt.amperes, for which there is an international standard unit named the watt.Therefore 15 kVA is 15 000 volt.amperes which, for a purely resistive load, can also be stated as 15 kilowatts.If the distribution voltage and type is known, you can then calculate the current in amps that will flow at that power rating if the load is purely resistive i.e. if the power factor is 1.If the power factor (pf) is less than 1 then, becausewatts = volts x amps x pfthen, at a given service voltage, more current must flow to produce the same apparent power as you would get with a purely resistive load.
No load current is excitation current, and is usually specified as a certain percent of base KVA rating at a specific voltage (often tested at 90, 100, and 110% rated voltage). This can be found in the test report for the specific transformer in question, or should be supplied by the manufacturer. Note it is specified as a percent of base, so if heated up from the high side, the current will be less than from the lowside - the transformer's excitation takes the same amount of power regardless of energizing voltage. You could test this roughly yourself by applying rated voltage to the lowside, and measuring the induced current. The load current for a single phase 11kVA transformer would be: 11K / (L-N voltage).