I am pretty sure you can figure this out on your own. Raise different numbers to the square, until you get a 4-digit result. Similary, calculate the cube of different numbers, until you get a 4-digit number. If you want the SAME number to be both a perfect square and a perfect cube, then it must be a power of 6. In that case, just experiment raising different numbers to the sixth power, until you get a 4-digit number.
4
4
x64 is not a perfect square any number if it is a 3-digit perfect square and ending with 4 it can be 144,324 ,484 and 784 because the number is ending with 4 but the tens digit is not matching to any of the option so it is not a perfect square
How about 64 which is cube and square number because 4*4*4 = 64 and 8*8 = 64
4 because 2x2=4 and 4 x 4 x 4=64
4,096 = (64)2 = (16)3
4
4
Well, let's see. Perfect cubes that are two digits: 27 64 Could it be 27? Well, 2+7 is 9, and that's a perfect square with a square root of 3, and the cube root of 27 is three. Looks like we've found our answer, especially since 6+4 = 10, which is NOT a perfect square.
4
7 * * * * * What? 73 = 343 which is the square of 18.52... hardly a perfect square! The correct answer is 9.
x64 is not a perfect square any number if it is a 3-digit perfect square and ending with 4 it can be 144,324 ,484 and 784 because the number is ending with 4 but the tens digit is not matching to any of the option so it is not a perfect square
9801
-1
How about 64 which is cube and square number because 4*4*4 = 64 and 8*8 = 64
992 = 9,801
It's 4. (31,622)2 = 999,950,884 .