4
To find how many two-digit numbers have digits whose sum is a perfect square, we first note that the two-digit numbers range from 10 to 99. The possible sums of the digits (tens digit (a) and units digit (b)) can range from 1 (1+0) to 18 (9+9). The perfect squares within this range are 1, 4, 9, and 16. Analyzing each case, we find the valid combinations for each perfect square, leading to a total of 36 two-digit numbers whose digits sum to a perfect square.
To find how many numbers from 10 to 93 have the sum of their digits equal to a perfect square, we first identify the possible perfect squares within the range of digit sums. The digit sum of a two-digit number ranges from 1 (for 10) to 18 (for 93). The perfect squares in this range are 1, 4, 9, and 16. By calculating the digit sums for each number from 10 to 93, we can determine that the numbers with digit sums equal to these perfect squares are 10-19 (sum = 1, 4, 9), and some others up to 93, yielding a total of 38 numbers.
x64 is not a perfect square any number if it is a 3-digit perfect square and ending with 4 it can be 144,324 ,484 and 784 because the number is ending with 4 but the tens digit is not matching to any of the option so it is not a perfect square
I am pretty sure you can figure this out on your own. Raise different numbers to the square, until you get a 4-digit result. Similary, calculate the cube of different numbers, until you get a 4-digit number. If you want the SAME number to be both a perfect square and a perfect cube, then it must be a power of 6. In that case, just experiment raising different numbers to the sixth power, until you get a 4-digit number.
11 squared is 121
To find how many two-digit numbers have digits whose sum is a perfect square, we first note that the two-digit numbers range from 10 to 99. The possible sums of the digits (tens digit (a) and units digit (b)) can range from 1 (1+0) to 18 (9+9). The perfect squares within this range are 1, 4, 9, and 16. Analyzing each case, we find the valid combinations for each perfect square, leading to a total of 36 two-digit numbers whose digits sum to a perfect square.
To find how many numbers from 10 to 93 have the sum of their digits equal to a perfect square, we first identify the possible perfect squares within the range of digit sums. The digit sum of a two-digit number ranges from 1 (for 10) to 18 (for 93). The perfect squares in this range are 1, 4, 9, and 16. By calculating the digit sums for each number from 10 to 93, we can determine that the numbers with digit sums equal to these perfect squares are 10-19 (sum = 1, 4, 9), and some others up to 93, yielding a total of 38 numbers.
x64 is not a perfect square any number if it is a 3-digit perfect square and ending with 4 it can be 144,324 ,484 and 784 because the number is ending with 4 but the tens digit is not matching to any of the option so it is not a perfect square
9801
121.
992 = 9,801
I am pretty sure you can figure this out on your own. Raise different numbers to the square, until you get a 4-digit result. Similary, calculate the cube of different numbers, until you get a 4-digit number. If you want the SAME number to be both a perfect square and a perfect cube, then it must be a power of 6. In that case, just experiment raising different numbers to the sixth power, until you get a 4-digit number.
It's 4. (31,622)2 = 999,950,884 .
Well, let's see. Perfect cubes that are two digits: 27 64 Could it be 27? Well, 2+7 is 9, and that's a perfect square with a square root of 3, and the cube root of 27 is three. Looks like we've found our answer, especially since 6+4 = 10, which is NOT a perfect square.
11 squared is 121
1024, square of 32.
What is the sum of greatest 3-digit 4-digit 5digit