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This is not possible, since there are only five single digit odd numbers, which are 1, 3, 5, 7 and 9.

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Q: What is a 6 digit number using only odd numbers 1 time each?
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Related questions

What is the largest 6 digit number using only even numbers using each number only once?

998,000


How many 3-digit numbers are there using 2 4 6 8 and 9?

There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125


What is the sum ratio of the number of one digit prime numbers and the number of one digit composite numbers?

There are four of each.


How many 3-digit numbers can be formed using 0123456789 when repetition is not allowed?

-123456786


How many 3 digit numbers can be found using 3 of the digits 6789 only once in each number?

4 options for the first digit, 3 options for the second digit, 2 options for the third digit. Multiply the number of options together, and you find how many 3-digit numbers you can get.


How many 4 digit numbers can be created using 5 6 7 and 8 using each digit only 1 time in a number?

24 = 4*3*2*1 of them


How many five digit numbers can be formed using the numbers 1-60 only using each number once in each combination?

61


How does the place of each digit help the value of the number?

the place of each digit help the value of the number by using your multuplication


How many 4-digit numbers can you write using 3 and 4?

For each number, there are four digits, and for each digit, there are two possibilities for digits: 3 or 4. So the number of 4-digit numbers is 2*2*2*2 = 16. The 4-digit numbers using 3 and 4 are: 3333 3334 3343 3344 3433 3434 3443 3444 4333 4334 4343 4344 4433 4434 4443 4444


How many 4 digit numbers can be made with numbers 1 to 6 using each number only once?

6*5*4*3=360


How many four digits numbers can be formed using 0123456789?

Assuming that the first digit of the 4 digit number cannot be 0, then there are 9 possible digits for the first of the four. Also assuming that each digit does not need to be unique, then the next three digits of the four can have 10 possible for each. That results in 9x10x10x10 = 9000 possible 4 digit numbers. If, however, you can not use the same number twice in completing the 4 digit number, and the first digit cannot be 0, then the result is 9x9x8x7 = 4536 possible 4 digit numbers. If the 4 digit number can start with 0, then there are 10,000 possible 4 digit numbers. If the 4 digit number can start with 0, and you cannot use any number twice, then the result is 10x9x8x7 = 5040 possilbe 4 digit numbers.


How many 4 digit numbers have 6 as their second digit?

There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.