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The automorphism group of a complete bipartite graph K_n,n is (S_n x S_n) semidirect Z_2.
It has a complete lack of any x-intercepts.
can't help about the edge connectivity but a graph is an animal you can see at the zoo - they stand out because they have very long necks and are generally decorated with brown oblongs.
A pie graph needs to be 100% full to be a pie. If you are trying to do the religions of a country you would put the religions and there percentages. A pie graph always needs to be 100% full
To graph an equation that is not in slope-intercept form, you can use the process of finding points on the graph and plotting them. Choose a few x-values, plug them into the equation to find the corresponding y-values, and plot those points on the graph. Then, connect the points with a smooth line to complete the graph.
No, the complete graph of 5 vertices is non planar. because we cant make any such complete graph which draw without cross over the edges . if there exist any crossing with respect to edges then the graph is non planar.Note:- a graph which contain minimum one edge from one vertex to another is called as complete graph...
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Yes, finding the longest path in a graph is an NP-complete problem.
The number of triangles in a complete graph with n nodes is n*(n-1)*(n-2) / 6.
The automorphism group of a complete bipartite graph K_n,n is (S_n x S_n) semidirect Z_2.
Yes!
No.
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The complexity of solving the k-color problem on a given graph is NP-complete.
Determining the minimum spanning tree of a graph is not an NP-complete problem. It can be solved in polynomial time using algorithms like Prim's or Kruskal's algorithm.
No.If the points on the graph are connected then they are already connected so it would be complete waste of time to connect them.
It has a complete lack of any x-intercepts.