(x - 10)(x - 9)
(x+7)(x+12)
(x - 12)(x - 7)
use the quadratic formula since there isn't a factor of 60 that when added together equals 19 The above answer is wrong because 4 and 15 are such numbers. x2 + 19x + 60 = x2 + 4x + 15x + 60 = x(x + 4) + 15(x + 4) = (x + 4)(x + 15)
-x2 + x + 42 = -[x2 - x - 42] = -[x2 - 7x + 6x - 42] = -[x*(x - 7) + 6*(x - 7)] = -(x - 7)*(x + 6)
(x - 10)(x - 9)
(x+7)(x+12)
(x + 12)(x + 7)
(x - 12)(x - 7)
Factor as : (x+9)(x+10) using the first terms ( x terms) multiply to x2; the last terms multiply to 90; the sum of 9x + 10 x = 19x
use the quadratic formula since there isn't a factor of 60 that when added together equals 19 The above answer is wrong because 4 and 15 are such numbers. x2 + 19x + 60 = x2 + 4x + 15x + 60 = x(x + 4) + 15(x + 4) = (x + 4)(x + 15)
x3 + 2x2 - 19x - 20 = x3 + x2 + x2 + x - 20x - 20 = x2(x + 1) - x(x + 1) - 20(x + 1) = (x + 1)(x2 + x - 20) = (x + 1)(x - 4)(x + 5)
-x2 + x + 42 = -[x2 - x - 42] = -[x2 - 7x + 6x - 42] = -[x*(x - 7) + 6*(x - 7)] = -(x - 7)*(x + 6)
Divide by x: x(x2 - 20x + 19); = x(x -1)(x - 19)
It is: (x+7)(x-6) when factored
(x + 7)(x - 6)
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