x3 + 2x2 - 19x - 20 = x3 + x2 + x2 + x - 20x - 20 = x2(x + 1) - x(x + 1) - 20(x + 1)
= (x + 1)(x2 + x - 20) = (x + 1)(x - 4)(x + 5)
a2+9a+20 = (a+4)(a+5) when factored
The sum of 20 added to itself 20 times is calculated by multiplying 20 by 20, resulting in 400. Therefore, the answer to the given equation is 400.
exactly 20 of them
2*2 - 12x +16 =0 4 - 12x +16 =0 -12x + 16 +4 =0 -12x + 20 =0 -12x = -20 x = 1.666666667
(x + 5) (x - 4)
19x+1x+37=0 First add the 19x and 1x together 20x+37=0 Next subtract 37 to the other side 20x=-37 Now divide both sides by 20 x=-20/37
4x2+2x-20 2x2+x-10 2x2+5x-4x-10 x(2x+5)-2(2x+5) (x-2)(2x+5)
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: 10 plus or minus 4 times the square root of 7. x = 20.583005244258363 x = -0.5830052442583629
2x2 + 3x - 20 = (x + 4)(2x - 5).
2x2+18x = 20 2x2+18x-20 = 0 x2+9x-10 = 0 (x+10)(x-1) = 0 x = -10 or x = 1
16=2x2x2x220=2x2x5GCF=2x2=4
If you are talking of 20 and 24 then factor both to prime factors. 20=2x2x5 24=2x2x2x3 circle the common ones. 2x2=4 the greatest common factor.
They are at: x = -2.5 and x = 4
2 x 2
a2+9a+20 = (a+4)(a+5) when factored
-4x2 + 6x + 40 = 0 ∴ -2x2 + 3x + 20 = 0 ∴ -2x2 - 8x + 5x + 20 = 0 ∴ -2x(x + 4) + 5(x + 4) = 0 ∴ (5 - 2x)(x + 4) = 0 ∴ x ∈ {5/2, -4}
Using the quadratic equation formula: x = 1 or x = -10