It is: 15 because 1*15 = 15 and 3*5 = 15
510. To be divisible by 3, it must be a multiple of 3. Thus the required number is a multiple of both 3 and 5, which will be a multiple of their lcm: lcm(3, 5) = 15. → 495 ÷ 15 = 33 → first multiple of 15 greater than 495 is 15 x 34 = 510 → 525 ÷ 15 = 35 → last multiple of 5 less than 525 is 15 x 34 x 510 → number required is 510.
If the number is even, it is a multiple of 2 If the sum of the digits make a number divisible by 3, the number is a multiple of 3 If the number ends in 5 or 0, the number is a multiple of 5 If the number is divisible by 2 and 3, the number is a multiple of 6 If the sum of the digits make a number divisible by 9, the number is a multiple of 9
No.3 is less than 5, thus cannot be a multiple of it; 3 is prime, therefore cannot be a multiple of any number besides 3 (which is one of its factors); by definition, 3 is ismply not a multiple of any number but 1 and 3.
Answer is 20.
15
number is both a prime number and a multiple of 5 = 5
15, obviously... reasoning: 3 times 5=15
Which number is a factor of 10 , but not a multiple of 5
3 and 5 are factors of 3270
It is: 15 because 1*15 = 15 and 3*5 = 15
The number you're looking for is 4. It's an even number, and when you add 5 to it, the result is 9, which is a multiple of 3.
The number 5 is both a factor and a multiple of 5, because5 and 1 are both factors of 5.5, 10, 15, 20, 25... are multiples of 5. The common number is 5.
to be an even multiple of 3 and 5 means it has to be a multiple of 2x3x5 = 30 answer is 5 numbers: 30, 60, 90, 120, 150
Any multiple of 15.
30.
510. To be divisible by 3, it must be a multiple of 3. Thus the required number is a multiple of both 3 and 5, which will be a multiple of their lcm: lcm(3, 5) = 15. → 495 ÷ 15 = 33 → first multiple of 15 greater than 495 is 15 x 34 = 510 → 525 ÷ 15 = 35 → last multiple of 5 less than 525 is 15 x 34 x 510 → number required is 510.