to be an even multiple of 3 and 5 means it has to be a multiple of 2x3x5 = 30
answer is 5 numbers: 30, 60, 90, 120, 150
Even multiples of 5 must end with a zero.
No, only every other multiple is odd. Example: 3,6,9,12,15,18
Every number has an even multiple - double it and there is the even multiple.
No. All the multiples of 4 are even numbers.
Yes, for example the multiples of 2 are: 2, 4, 6, 8, 10, 12, 14, ......etc. (all even numbers are multiples of 2) or multiples of 3 are 3, 6, 9, 12, 15, 18, 21, ....... etc.
Yes, All multiples of an even number are themselves even. 4 is an even number, so its multiples are all even.
4 is an even number. The multiples can only be even.
Multiples of any even number will always stay even.An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. The multiples of 8 are even.
50 is an even number so ALL its multiples are even...
Yes, integer multiples of even numbers are always even.
Multiples of 5 in even numbers occur when an even number is divisible by 5. Since even numbers are integers that are divisible by 2, a multiple of 5 in an even number would be a number that is divisible by both 2 and 5. This means the number must be a multiple of 10, as 10 is the least common multiple of 2 and 5. Examples of such numbers include 10, 20, 30, and so on.
All multiples of even numbers will equal an even number.
Even multiples of 5 must end with a zero.
Even numbers are the multiples of 2 and are those numbers which end with one of {0, 2, 4, 6, 8}; odd numbers are those which are not multiples of two and are those numbers which end with {1, 3, 5, 7, 9}. When an even number is multiplied by an even or odd number the result is always an even number. 4 is an even number; thus all its multiples are even numbers. Any number that ends with a 3 is an odd number. There are no numbers which are both odd and even; therefore no multiple of 4 can end in a 3.
No number can satisfy these conditions: To have a remainder of 1 when divided by 6, the number must be odd (as all multiples of 6 are even and an even number plus 1 is odd) To have a remainder of 2 when divided by 8, the number must be even (as all multiples of 8 are even and an even number plus 2 is even) No number is both odd and even. → No number exists that has a remainder of 1 when divided by 6, and 2 when divided by 8.
No for example 11X12 = 132
Yes, because 2 is even,and it goes into every even number equally.