The Pythagoream Thereom is a^2 + b^2 = c^2. Written out it is a squared plus b squared equals c squared.
Because it is mathematically incorrect. a^2 + b^2 = c^2 Take square root of both sides. SQRT (a^2 + b^2) = c So you see, it is not a plus b equal c.
pythagoras
no
b = sqrt32 or 4 root 2
The Pythagoream Thereom is a^2 + b^2 = c^2. Written out it is a squared plus b squared equals c squared.
4
Because it is mathematically incorrect. a^2 + b^2 = c^2 Take square root of both sides. SQRT (a^2 + b^2) = c So you see, it is not a plus b equal c.
a squared plus b squared is c squared
pythagoras
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.
Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.
The Pythagoream Thereom is a^2 + b^2 = c^2. Written out it is a squared plus b squared equals c squared.
Pascal
you use A squared plus B squared equals C squared
no
b = sqrt32 or 4 root 2