To get a quotient and a remainder, you would need to do a division, not a multiplication.
84.5
26.1538
The quotient is 2 with a remainder of 6
Yes. The remainder cannot be more that the divisor but there is no issue with it being greater than the quotient. For example, if you divide 5 by 3, 5/3 = 1 and remainder 2 (out of 3) So you get quotient = 1, remainder = 2.
No. When you divide a number by another number, let's say 26/4, you can't always get a perfect number. In this case, 6*4 is 24, and you have 2 "remainder", or 2 left over. The quotient is the whole answer, in this case 6 remainder 2. So the remainder is part of the quotient, but not the whole quotient itself.
Quotient =3x 3 −x 2 −x−4 Remainder =−5
84.5
From the Division Algorithm for Polynomials theorem,f(x) = q(x)g(x) + r(x) or we say:dividend = (quotient)(divisor) + (remainder)In our case,quotient = x^2 - 5x - 6; divisor = x - 3; and remainder = 5.Substitute what you know into the formula, and you will have:f(x) = (x^2 - 5x - 6)(x - 3) + 5f(x) = x^3 - 5x^2 - 6x - 3x^2 + 15x + 18 + 5f(x) = x^3 - 5x^2 - 3x^2 - 6x + 15x + 18 + 5f(x) = x^3 - 8x^2 + 9x + 23 (this is the required polynomial)
26.1538
That means that you divide one polynomial by another polynomial. Basically, if you have polynomials "A" and "B", you look for a polynomial "C" and a remainder "R", such that: B x C + R = A ... such that the remainder has a lower degree than polynomial "B", the polynomial by which you are dividing. For example, if you divide by a polynomial of degree 3, the remainder must be of degree 2 or less.
The quotient is 2 with a remainder of 6
Yes. The remainder cannot be more that the divisor but there is no issue with it being greater than the quotient. For example, if you divide 5 by 3, 5/3 = 1 and remainder 2 (out of 3) So you get quotient = 1, remainder = 2.
No. When you divide a number by another number, let's say 26/4, you can't always get a perfect number. In this case, 6*4 is 24, and you have 2 "remainder", or 2 left over. The quotient is the whole answer, in this case 6 remainder 2. So the remainder is part of the quotient, but not the whole quotient itself.
Since binary is about 2 digits do the calculatio asmentioned below: We have 146,right.... 1.)Divide it with 2 so is there any remainder ,no, so 0,quotient is 71 2.)Now divide the quotient with 2, now remainder is 1, quotient is,35 3.) Again repeat the same procedure, now remainder is 1, quotient is 17 4.) same process continues,remainder now 1, quotient is 8, 5.)Same, remainder is 0,quotient is 4 6.)Same, remainder is 0,quotient is 2 7.)Same, remainder is 0,quotient is 1 8.)Same, remainder is 1,quotient is 0. Now atlast consider all the remainders from bottom... You will get 10001110 is your answer in binary.
3124.5
6.6667
-9