No, they cannot with real numbers. With complex numbers it is possible.
It means that the question has been written by someone who does not know what the word "polynomial" means, or else that this is a copy-and-paste by someone who knows even less! Only a trinomial can be written as a product of two binomials. No polynomial of any other order can!
The two binomials can be written as (x - a)(x + a), for any constant a. Proof: Expand using FOIL: (x - a)(x + a) = x2 + xa - xa - a2 Group: (x - a)(x + a) = x2 - a2 x2 - a2 is a difference of squares. Thus, the product of (x - a) and (x + a) is a difference of squares.
No. A counter-example proves the falsity: Consider the two binomials (x + 2) and (x - 2). Then (x + 2)(x - 2) = x2 - 2x + 2x - 4 = x2 - 4 another binomial.
Let a, b, c, d Є C, where C is the field of complex numbers.Let m, n, p, q Є N, where N is the field of natural numbers, including 0.If w, x, y, z Є C are unknown, the product of the two binomials (awm + bxn) and (cyp + dzq) is equal to the following:acwmyp + adwmzq + bcxnyp + bdxnzq.
a²-b²
distributive.
distributive
(a-b) (a+b) = a2+b2
no please give me 5 riddles about product of 2 binomial
the two consecutive positive integers whose product is 380 19 20
No, they cannot with real numbers. With complex numbers it is possible.
multiply the 1st term with whole bracket and the 2nd term with whole bracket
It means that the question has been written by someone who does not know what the word "polynomial" means, or else that this is a copy-and-paste by someone who knows even less! Only a trinomial can be written as a product of two binomials. No polynomial of any other order can!
no, because some examples are: (a-2)(a+2) = a^2-4 (binomial) & (a+b)(c-d) = ac-ad+bc-db (polynomial) but can 2 binomials equal to a monomial?
Binomials are algebraic expressions of the sum or difference of two terms. Some binomials can be broken down into factors. One example of this is the "difference between two squares" where the binomial a2 - b2 can be factored into (a - b)(a + b)
The product is(the product of the first term of each)plus(the product of the last term of each) plus(the product of the first term of the first and the last term of the second) plus(the product of the first term of the second and the last term of the first).