(a-b) (a+b) = a2+b2
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no, because some examples are: (a-2)(a+2) = a^2-4 (binomial) & (a+b)(c-d) = ac-ad+bc-db (polynomial) but can 2 binomials equal to a monomial?
distributive
multiply the 1st term with whole bracket and the 2nd term with whole bracket
The product is(the product of the first term of each)plus(the product of the last term of each) plus(the product of the first term of the first and the last term of the second) plus(the product of the first term of the second and the last term of the first).
First ("first" terms of each binomial are multiplied together)Outer ("outside" terms are multiplied-that is, the first term of the first binomial and the second term of the second)Inner ("inside" terms are multiplied-second term of the first binomial and first term of the second)Last ("last" terms of each binomial are multiplied)The general form is: (A+B)(C+D) = AC + AD + BC + BDWhere AC is the first, AD is the outer, BC is the inner, and BD is the last.So:(X+4)(X-5)= X^2 - 5X + 4X - 20= X^2 - 1X - 20