Find the perimeter of a right triangle with legs measuring 3 and 4
the square root of 116
Area = 0.5*10*4 = 20 square units
7.211
4 x sqrt2
Find the perimeter of a right triangle with legs measuring 3 and 4
the square root of 116
6 feet
Area = 0.5*10*4 = 20 square units
41
7.211
\32 or 4\2
4 x sqrt2
The area of a right triangle that has legs 7 cm and 4 cm long can be calculated using the fact that a right triangle is half of a rectangle. The area of a rectangle is l*h, so the area of a right triangle is l*h/2. In this case, the area is 14 cm^2.
It's not possible to have a right angle triangle with sides of equal length. The sides on a right angle triangle are always in the ratio 3:4:5.
6 square feet
The length of the hypothesis of a right triangle with legs of 4 would depend on the units used for measurement. If the legs are measured in the same units, the length of the hypotenuse can be found using the Pythagorean theorem, which states that the square of the hypotenuse is equal to the sum of the squares of the legs. In this case, the length of the hypotenuse would be 4√2.