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What is the area of a right triangle with legs 5.5 and 4?
Area = 1/2*5.5*4 = 11 square units
What is the area of a right triangle with legs of 3 and 4 feet?
6 square feet
A right triangle has legs 6cm and 8cm How far from the vertex must this triangle be cut by a line parallel to the longer leg so that the area of the smaller right triangle is equal to the area of the?
it is 24in The area of the first triangle is 24 [(6*8)/2]. The area of the smaller triangle is 12 [24/2]. The two legs will have a relationship of [4/3x to x], the same as any right triangle.
What is the area of a triangle with the lengths of 4 and 10?
Information about the lengths of two sides of a triangle is insufficient to determine its area.
Calculate the perimeter of a right triangle with legs measuring 3 and 4?
Find the perimeter of a right triangle with legs measuring 3 and 4
What is the area of a right triangle that has legs 7 cm and 4 cm long?
The area of a right triangle that has legs 7 cm and 4 cm long can be calculated using the fact that a right triangle is half of a rectangle. The area of a rectangle is l*h, so the area of a right triangle is l*h/2. In this case, the area is 14 cm^2.
What is the area of a right triangle with legs 5.5 and 4?
Area = 1/2*5.5*4 = 11 square units
What is the area of a right triangle with legs of 3 and 4 feet?
6 square feet
A right triangle has legs 6cm and 8cm How far from the vertex must this triangle be cut by a line parallel to the longer leg so that the area of the smaller right triangle is equal to the area of the?
it is 24in The area of the first triangle is 24 [(6*8)/2]. The area of the smaller triangle is 12 [24/2]. The two legs will have a relationship of [4/3x to x], the same as any right triangle.
What is the area of a triangle with the lengths of 4 and 10?
Information about the lengths of two sides of a triangle is insufficient to determine its area.
What is the area of a triangle with the heght of 5 and the base of 4?
A triangle is half a square The area of a square is height × width(base) So, the area of a triangle is height × base ÷ 2 5×4÷2 = 10
Given the legs a and b of a triangle are 3 and 4 then the hypotenuse is?
Given the legs a and b of a triangle are 3 and 4, the hypotenuse is: 5
Calculate the perimeter of a right triangle with legs measuring 3 and 4?
Find the perimeter of a right triangle with legs measuring 3 and 4
What is the area of a triangle with base of 4'' and a height of 10''?
The area of a triangle is (1/2) x (length of the base) x (height of the triangle). You ought to be able to handle it from this point.
Find the hypotenuse of a right triangle whose legs are 4 cm and 10 cm?
the square root of 116
What is the area of an equilateral triangle inscribed in a circle of radius 4cm?
Two vertices of the triangle and the centre of the circle make a smaller equilateral triangle with legs of 4 cm and the included angle is 360/3 = 120 degrees.Therefore the area of each of these sub-triangles = 1/2*ab*sin(C) = 1/2*4*4*sin(120) = 1/2*4*4*1/2 = 4 cm2.And so the area of the inscribed triangle is 12 cm2.Two vertices of the triangle and the centre of the circle make a smaller equilateral triangle with legs of 4 cm and the included angle is 360/3 = 120 degrees.Therefore the area of each of these sub-triangles = 1/2*ab*sin(C) = 1/2*4*4*sin(120) = 1/2*4*4*1/2 = 4 cm2.And so the area of the inscribed triangle is 12 cm2.Two vertices of the triangle and the centre of the circle make a smaller equilateral triangle with legs of 4 cm and the included angle is 360/3 = 120 degrees.Therefore the area of each of these sub-triangles = 1/2*ab*sin(C) = 1/2*4*4*sin(120) = 1/2*4*4*1/2 = 4 cm2.And so the area of the inscribed triangle is 12 cm2.Two vertices of the triangle and the centre of the circle make a smaller equilateral triangle with legs of 4 cm and the included angle is 360/3 = 120 degrees.Therefore the area of each of these sub-triangles = 1/2*ab*sin(C) = 1/2*4*4*sin(120) = 1/2*4*4*1/2 = 4 cm2.And so the area of the inscribed triangle is 12 cm2.
What is the area of a right triangle that is 4cm by 8cm?
The area of a right-angle triangle is half of the area of a rectangle 8cm x 4cm. Find the rectangle area and divide by half to find the area of the right-angle triangle. Therefore: 8 x 4 / 2 = 16cm2 * * * * * The above answer assumes that the two given lengths are the shorter legs of the triangle. It is, however, possible that these are the hypotenuse and one leg. In that case, the second leg is 4*sqrt(2) cm and the area of the triangle is 4 * 4*sqrt(2) / 2 = 8*sqrt(2) = 11.31 cm2.
