the distance from A to B is 24Km
If A times B = C and C is not 0, then the related division problems are C/A = B and C/B = A.
x(-b)=m(x-c)
With no knowledge about A, B, C and D or the relation between them, it is impossible to give an answer.
The product can be expressed as abc.
A=0 b=0 c=0
The product of the means equals the product of the extremes. In other words, if A is to B as C is to D, then B times C equals A times D, so... A = B x C ÷ D B = A x D ÷ C C = A x D ÷ B D = B x C ÷ A
the distance from A to B is 24Km
If A times B = C and C is not 0, then the related division problems are C/A = B and C/B = A.
x(-b)=m(x-c)
ax - b = c Add 'b' to both sides ax = c + b Divide both sides by 'a' x = (c + b) / a The answer!!!!!
Well, darling, b times c equals the product of b and c. In other words, you multiply those two numbers together to get your answer. Math can be a real hoot, can't it?
Any set of the form {a,a,a,a,b,b,b,b,c,c} where a<b<c.
When you go to the shop press A(3 or 2 times then enter:B,C,B,C,C,A,B,A
well the only answer i can so far come up with is: a=1 b= -1 c=0 so then (a+b)=(c*c)=(a*c) ...............(0)=(0)=(0) ......................0 ok if that is what your looking for Great! just know that i am not a math wiz. :)
It equals b times c.
A c# e c# (repeat 4 times) g# c# e c# (repeat 4 times) f# (low) c# f# (high) c# (repeat 4 times) a d f# (high) d (repeat 4 times) e c# b a i heard that you've e e c# b a settled down that you've e e c# b a found a girl and you're e e c# b a married no-o-ow e c# b a i heard that your f# (high) c# a dreams came true that's all i know, good luck!