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A stone falls from rest how fast is it falling after 10 seconds?
Speed = (acceleration) times (time)Acceleration = gravity = 9.8 meters (32.2 feet) per second2Speed = 10g = 98 meters (322 feet) per second
If the speed of an object changes from 121 meters per second to 98 meters per second during a time interval of 12 seconds what is the acceleration of the object?
Acceleration = change in velocity/time a = (v - u) /t where a= acceleration, v= velocity, u= initial velocity & t= time. u = 121 m/s v = 98 m/s t = 12 m/s a = (98 - 121) /12 a = -23/12 a = -1.91667 m/s2
If the speed of an object changes from 121 ms to 98 ms during a time interval of 12s what is the acceleration of the object?
Average acceleration during the time interval = (change on speed) / (time for the change) =(98 - 121) / (12) = -23/12 = negative (1 and 11/12) meters per second2
Why are the units for acceleration meters per second?
Acceleration is not measured in meters/second. Meters/second is a unit of speed. Since acceleration is defined as change of speed divided by time, the units are meters/second/second, usually written as meters/second2.
What is the unit of acceleration measured in kilometers per hour?
Kilometers per hour is used to measure speed, not acceleration. In SI, the acceleration is commonly measured in meters per square second.Kilometers per hour is used to measure speed, not acceleration. In SI, the acceleration is commonly measured in meters per square second.Kilometers per hour is used to measure speed, not acceleration. In SI, the acceleration is commonly measured in meters per square second.Kilometers per hour is used to measure speed, not acceleration. In SI, the acceleration is commonly measured in meters per square second.
A stone falls from rest how fast is it falling after 10 seconds?
Speed = (acceleration) times (time)Acceleration = gravity = 9.8 meters (32.2 feet) per second2Speed = 10g = 98 meters (322 feet) per second
If the speed of an object changes from 121 meters per second to 98 meters per second during a time interval of 12 seconds what is the acceleration of the object?
Acceleration = change in velocity/time a = (v - u) /t where a= acceleration, v= velocity, u= initial velocity & t= time. u = 121 m/s v = 98 m/s t = 12 m/s a = (98 - 121) /12 a = -23/12 a = -1.91667 m/s2
Ten second after starting from rest a freely falling object will have the speed of about?
98 m/s, assuming the acceleration due to gravity is 9.8 m/s^2.
Gravity causes all falling objects to accelerate at a rate of 98 meters per seconds?
The acceleration due to gravity is 9.8 meters per second squared, not 98. This means that an object in free fall will increase its speed by 9.8 m/s every second.
How many meters in 98 inches?
98 inches = 2.4892 meters.
How many foot in 98 meters?
98 meters = 321.52231 feet
If the speed of an object changes from 121 ms to 98 ms during a time interval of 12s what is the acceleration of the object?
Average acceleration during the time interval = (change on speed) / (time for the change) =(98 - 121) / (12) = -23/12 = negative (1 and 11/12) meters per second2
98 meters equals how many milimeters?
98 meters = 98,000 millimeters
Why are the units for acceleration meters per second?
Acceleration is not measured in meters/second. Meters/second is a unit of speed. Since acceleration is defined as change of speed divided by time, the units are meters/second/second, usually written as meters/second2.
98 meters equals how many millimeters?
98 meters equals how many millimeters?
The acceleration of gravity means that for each second that passes falling objects move 98 meters?
No, that's not correct.The acceleration of gravity means that for each second that passes, falling objects fallat a speed that's 9.8 meters per second fasterthan it was one second earlier.
What is an acceleration that is 9.8 meters?
An acceleration of 9.8 meters per second squared is equivalent to the acceleration due to gravity on Earth. This value represents the rate at which the speed of an object changes per second when it falls freely under gravity near the Earth's surface.
