In order to untangle this mess, let's assume that the acceleration is entirely a change in speed,
and that the direction is not changing.
Also, I have this feeling that you're referring to the acceleration and speed of the same moving object.
That makes it even messier.
I know what the bottom line is going to be, but before I go there, I'll go through some math:
Here are the equations for a body moving in a straight line.
X0 = the position it started at
X = its position after 't' seconds
V0 = the speed it started out with
V = its speed after 't' seconds
a = its acceleration
X = X0 + V0 t + 1/2 a t2
V = V0 + a t
A = a
You asked for the object's (acceleration) x (speed).
As you would expect, if the acceleration is not zero, then that product keeps changing,
because the speed keeps changing.
(Acceleration) x (speed) = a (V0 + a t) = aV0 + a2t.
If the object started out from rest ... no speed when the clock started ... then it's just [ a2t ] .
Technically, that's the answer ... (provided the acceleration is constant).
Physically, in the real world, it has no physical meaning. Don't believe me ? Consider the 'dimensions'
or units of this quantity: "square meters per cubic seconds". I'll take 3 of 'em. Wrap 'em up.
The speed or velocity of a train has no bearing on its acceleration.
Speed = (initial speed) plus (acceleration) x (time) = 0 + (5) x (3) = 15 meters per second.
If starting from rest, Distance = 1/2 (acceleration) x (time)2 . Otherwise, Distance = 1/2 (initial speed + final speed) x (time)
You have to know how long it takes to get to 90 mph to solve this. Speed = acceleration x time
Acceleration is the time rate of change of speed. Acceleration = speed/time.
Speed = Time x acceleration
The speed can be found by multiplying the acceleration by the time. So, speed = acceleration x time.
You can calculate speed by dividing the force by the mass to get acceleration, and then multiplying the acceleration by time. Speed = acceleration x time.
The speed or velocity of a train has no bearing on its acceleration.
Speed = (initial speed) plus (acceleration) x (time) = 0 + (5) x (3) = 15 meters per second.
Acceleration = 0 Speed = constant Distance = (speed) x (time)
If starting from rest, Distance = 1/2 (acceleration) x (time)2 . Otherwise, Distance = 1/2 (initial speed + final speed) x (time)
You can find the final speed by using the formula: final speed = initial velocity + (acceleration * time). Plug in the given values for initial velocity, acceleration, and time into the formula to calculate the final speed.
To find acceleration from a speed-time graph, you need to calculate the slope of the speed-time graph. The slope at any point on the speed-time graph represents the acceleration at that specific time. If the speed-time graph is linear, then the acceleration will be constant. If the speed-time graph is curved, you can find the acceleration by calculating the slope of the tangent line at a specific point.
You have to know how long it takes to get to 90 mph to solve this. Speed = acceleration x time
Acceleration is the time rate of change of speed. Acceleration = speed/time.
Acceleration is directly proportional to the change in speed. If the speed increases, acceleration is positive. If the speed decreases, acceleration is negative. The magnitude of acceleration is determined by the rate at which the speed changes.