Assuming that the phrase "doubled by 2" is tautological, the expression for a number multiplied by 2 (or a number doubled) is 2n.
3q + 2z, although it could be 2*(3q+z)
Any number when doubled becomes even. Thus the key part of the question is identifying a 3 digit even number that you can add 2 to to become a 4 digit number. The answer is 998. Thus to find the original number we need to do 998/2. This calculates to 499.
Doubled # = original# * 2^(times it doubles)
So, to put your question in an algebraic expression, it should look something like this: X/2 = 2X - 3 Then you would just solve... X = 2(2X - 3) X = 4X - 6 -3X = -6 X = 2
Multiply it by two. So to double 5 you would do 5*2 (5x2). Then 5 would be doubled.
The algebraic expression "twice a number z" can be represented as 2z. In this expression, the variable z represents the unknown number, and multiplying it by 2 gives you twice that number. This expression can be used in algebraic equations and formulas to represent scenarios where a number needs to be doubled.
3q + 2z, although it could be 2*(3q+z)
The quotient of a number and 2 is the same as the difference of the number doubled and 3.
There is no such number, although I am struggling to prove it.
Any number when doubled becomes even. Thus the key part of the question is identifying a 3 digit even number that you can add 2 to to become a 4 digit number. The answer is 998. Thus to find the original number we need to do 998/2. This calculates to 499.
its an exponent it means squared or doubled because its a 2
Doubled # = original# * 2^(times it doubles)
51 x 2 = 102
So, to put your question in an algebraic expression, it should look something like this: X/2 = 2X - 3 Then you would just solve... X = 2(2X - 3) X = 4X - 6 -3X = -6 X = 2
Multiply it by two. So to double 5 you would do 5*2 (5x2). Then 5 would be doubled.
(100 - 6)/2 = 47 The prime number 47 when doubled is six less than one hundred.
16 i would belive the number to be as it is being doubled everytime.