So, to put your question in an algebraic expression, it should look something like this:
X/2 = 2X - 3
Then you would just solve...
X = 2(2X - 3)
X = 4X - 6
-3X = -6
X = 2
x/2 = 2x - 3 x = 4x - 6 3x - 6 = 0 3x = 6 x = 2 Check it. 2/2 = 4 - 3 It checks.
i dont know so you divied the
810: quotient 1, remainder 1
no, it simply multiplies the quotient by 1 (the multiplicative identity).
The smallest number that when doubled contains all the same digits in a different order.
The quotient of a number and 2 is the same as the difference of the number doubled and 3.
9X-X/6
The quotient is doubled. 8/4 = 2 8/2 = 4
x/2 = 2x - 3 x = 4x - 6 3x - 6 = 0 3x = 6 x = 2 Check it. 2/2 = 4 - 3 It checks.
i dont know so you divied the
The number 1. Unless the number is 0, in which case, the quotient is not defined.
When the plate separation of a capacitor is doubled, the potential difference across each capacitor remains the same.
As long as the number is not zero, the quotient remains unchanged. If the multiplier is zero then the quotient is undefined.
When an integer is divided by 1 same integer number will be the quotient
810: quotient 1, remainder 1
If the volume is doubled and the number of molecules is doubled while the temperature is held constant, the pressure of the gas sample will remain the same. This is because both the volume and the number of molecules increased by the same factor, resulting in no net change in pressure according to the ideal gas law.
no, it simply multiplies the quotient by 1 (the multiplicative identity).