0
Want this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
What is the perpendicular bisector equation joining the points of s 2s and 3s 8s on the Cartesian plane showing work?
Points: (s, 2s) and (3s, 8s) Slope: (8s-2s)/(3s-s) = 6s/2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) => 3y-15s = -1(x-2s) => 3y = -x+17x Perpendicular bisector equation in its general form: x+3y-17s = 0
What is the perpendicular bisector equation of a line joined by the points of s 2s and 3s 8s showing key stages of work?
It is found as follows:- Points: (s, 2s) and (3s, 8s) Slope: (2s-8s)/(s-3s) = -6s/-2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) Multiply all terms by 3: 3y-15s = -1(x-2s) => 3y = -x+17s In its general form: x+3y-17s = 0
How do you determine the equation for the perpendicular bisector of the straight line joining the points s 2s and 3s 8s?
A = (s, 2s), B = (3s, 8s) The midpoint of AB is C = [(s + 3s)/2, (2s + 8s)/2] = [4s/2, 10s/2] = (2s, 5s) Gradient of AB = (8s - 2s)/(3s - s) = 6s/2s = 3 Gradient of perpendicular to AB = -1/(slope AB) = -1/3 Now, line through C = (2s, 5s) with gradient -1/3 is y - 5s = -1/3*(x - 2s) = 1/3*(2s - x) or 3y - 15s = 2s - x or x + 3y = 17s
What is the answer to 5s - 6 equals 2s?
5s - 6 = 2s, ie 5s - 2s = 6, ie 3s = 6, ie s = 2
How do you solve 7r plus 2s plus 5r plus s?
Simplified its 12r+3s
2s plus s plus 12 equals 132?
2s + s + 12 =132 ie 3s = 132 -12 3s = 120 s = 40
What is the answer to this equation 2s plus s plus 12 equals 132?
2s + s + 12 = 132 3s + 12 = 132 3s = 132 - 12 3s = 120 s = 40
What is the perpendicular bisector equation joining the points of s 2s and 3s 8s on the Cartesian plane showing work?
Points: (s, 2s) and (3s, 8s) Slope: (8s-2s)/(3s-s) = 6s/2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) => 3y-15s = -1(x-2s) => 3y = -x+17x Perpendicular bisector equation in its general form: x+3y-17s = 0
What is the perpendicular bisector equation of a line joined by the points of s 2s and 3s 8s showing key stages of work?
It is found as follows:- Points: (s, 2s) and (3s, 8s) Slope: (2s-8s)/(s-3s) = -6s/-2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) Multiply all terms by 3: 3y-15s = -1(x-2s) => 3y = -x+17s In its general form: x+3y-17s = 0
How do you determine the equation for the perpendicular bisector of the straight line joining the points s 2s and 3s 8s?
A = (s, 2s), B = (3s, 8s) The midpoint of AB is C = [(s + 3s)/2, (2s + 8s)/2] = [4s/2, 10s/2] = (2s, 5s) Gradient of AB = (8s - 2s)/(3s - s) = 6s/2s = 3 Gradient of perpendicular to AB = -1/(slope AB) = -1/3 Now, line through C = (2s, 5s) with gradient -1/3 is y - 5s = -1/3*(x - 2s) = 1/3*(2s - x) or 3y - 15s = 2s - x or x + 3y = 17s
What is 3s plus 4t plus 2s plus 5s plus 6t equals?
3s + 4t + 2s + 5s + 6tGroup all of the like 's' terms & 't' terms together:(3s+2s+5s) + (4t + 6t)10s + 10t or 10(s+t)
What is the difference between a 2s orbital and a 3s orbital?
The main difference between a 2s orbital and a 3s orbital is their energy levels. A 3s orbital is at a higher energy level than a 2s orbital. Additionally, the 3s orbital has a larger size and higher probability of finding an electron farther from the nucleus compared to a 2s orbital.
What is the answer to 5s - 6 equals 2s?
5s - 6 = 2s, ie 5s - 2s = 6, ie 3s = 6, ie s = 2
What is in its general form the perpendicular bisector equation meeting the line segment of s 2s and 3s 8s at its midpoint?
Points: (s, 2s) and (3s, 8s) Slope: 3 Perpendicular slope: -1/3 Midpoint: (2s, 5s) Equation in its general form: x+3y-17 = 0
What is 5 plus 2 stars plus stars equals 3 stars -stars plus 8?
5 + 2s + s = 3s - s + 8 Combining like terms on the same side: 5 + 3s = 2s + 8 Subtracting 2s from both sides: 5 + s = 8 Subtracting 5 from both sides: s = 3
How do you solve 7r plus 2s plus 5r plus s?
Simplified its 12r+3s
Is 97 in the 3s 5s or 2s?
NO
