The square root of 2 and the square root of 3 both qualify. Both of these are irrational and both are greater than 1 but less than 2. There are, of course, uncountably infinite different irrational numbers in the range between 1 and 2 and countably infinite rational numbers.
An example of an irrational number that is less than 2 but greater than 1.5 is (\sqrt{3}). This number is approximately 1.732, which falls within the specified range. Another example could be (\pi - 1), which is approximately 2.14 but still less than 2.
A negative irrational number, such as -sqrt(2), or -pi.
+sqrt(65)
-2
the square root of 10
To 4.5, add the difference between the two numbers (0.1), multiplied by some irrational number that is less than 1 (or divided by an irrational number greater than 1). For example:4.5 + 0.1 / pi
A negative irrational number, such as -sqrt(2), or -pi.
+sqrt(65)
100% equals the number. Less than 100% is less than the number. Greater than 100% is greater than the number.
-2
the square root of 10
No, the set of irrational numbers has a cardinality that is greater than that for rational numbers. In other words, the number of irrational numbers is of a greater order of infinity than rational numbers.
It can be greater than or less than it.
-sqrt(26)
- sqrt(26)
The square root of 2.
There is no such number. For if you considered 49.99 to be such a number, then 49.995 is a greater number and it is less than 50. And then 49.9955 is even greater and still less than 50. This process can go on without end.