Rewrite as,
int[sinx 1/2 ]
= - (2/3)cosx 3/2 + C
==================or
= - (2/3)sqrt[cosx 3] + C
==================
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sin2x is the conventional way of writing (sinx)2; it does not denote the sine of sinx as one might expect. So the square root is just sinx.
it is not possible to get the Integral of cos2x log cosx-sinx coax plus since there are no symbols given in the equation.
replace square root o x with t.
square root x
The square root of 28 is an irrational number that can't be expressed as a fraction