We're assuming the dimensions of the pavers are given in inches,and of the patio are given in feet.The area of the patio is: (11 x 11 x 144) square inchesThe area allowed for each paver is (17 x 17) square inches.The number required is: (11 x 11 x 144) / (17 x 17) = 60.29You need 61 of them, but part of the last one won't be used.
Area of a rectangle = (length) x (width) = 4 x 11 = 44 square iunches
Assuming that the cylinder has no end caps then the surface area, A = 2πrh Substituting the given dimensions then A = 2π x 11 x 11 = 760.27 in² (2dp). If there are end caps then one these has an area of πr² so together they have an area of 2πr² = 2π x 11² = 760.27........so the combined area = 1520.54 in²
The volume of a suitcase with the dimensions of 15 inches x 14 inches x 11 inches is 2310 inches3.
If you give 3 dimensions (99, 78, 140) then you think volume not area. Area is the product of two dimensions: length and width
We're assuming the dimensions of the pavers are given in inches,and of the patio are given in feet.The area of the patio is: (11 x 11 x 144) square inchesThe area allowed for each paver is (17 x 17) square inches.The number required is: (11 x 11 x 144) / (17 x 17) = 60.29You need 61 of them, but part of the last one won't be used.
Area of a rectangle = (length) x (width) = 4 x 11 = 44 square iunches
Dimensions for a case of US 8.5" x 11" paper: 9" x 12" x 17"
Dimensions for a case of US 8.5" x 11" paper: 9" x 12" x 17"
2 x (11 x 3) + 2 x (11 x 3) + 2 x (3 x 3) = 150 square feet
Assuming that the cylinder has no end caps then the surface area, A = 2πrh Substituting the given dimensions then A = 2π x 11 x 11 = 760.27 in² (2dp). If there are end caps then one these has an area of πr² so together they have an area of 2πr² = 2π x 11² = 760.27........so the combined area = 1520.54 in²
Letting x be the length of the rectangle and (x - 8) be the width of the rectangle,x(x - 8) = 153,subtracting 153 from each side, x2 - 8x - 153 = 0,solving for x, (x - 17)(x + 9) = 0, then x = 17 or x = -9,substituting 17 for x, the dimensions of the rectangle are 17cm and 9cm.
The volume of a suitcase with the dimensions of 15 inches x 14 inches x 11 inches is 2310 inches3.
If you give 3 dimensions (99, 78, 140) then you think volume not area. Area is the product of two dimensions: length and width
17 multiplied by 11 is 187
You can't tell the rectangle's dimensions if you only know its area. There are an infinite number of rectangles, with different dimensions, that all have the same area. Here are some possibilities: 1 x 175 4 x 43.75 5 x 35 7 x 25 10 x 17.5 15 x 11-2/3 20 x 8.75 Each of these has an area of 175. There are still an infinite number more.
You can't. The area doesn't tell you the dimensions. Even if you know the area,there are an infinite number of different rectangles, all with different dimensions,that all have the same area.Here are dimensions of a few rectangles that all have area of 60:1 x 601.5 x 402 x 302.5 x 243 x 204 x 154.8 x 12.55 x 126 x 107.5 x 8