To find the area of a triangle with sides measuring 7 m, 5 m, and 12 m, we can use Heron's formula. First, calculate the semi-perimeter ( s = \frac{7 + 5 + 12}{2} = 12 ) m. The area ( A ) is then given by ( A = \sqrt{s(s-a)(s-b)(s-c)} ), where ( a, b, c ) are the side lengths. However, since the sum of the lengths of the two shorter sides (7 m and 5 m) is less than the length of the longest side (12 m), this triangle cannot exist, and thus the area is 0.
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To find the area of a triangle with sides measuring 7 m, 5 m, and 12 m, we can use Heron's formula. First, calculate the semi-perimeter (s): (s = (7 + 5 + 12) / 2 = 12) m. The area (A) can be calculated as (A = \sqrt{s(s-a)(s-b)(s-c)}), where a, b, and c are the side lengths. However, since 7 m + 5 m is not greater than 12 m, these lengths do not form a valid triangle. Therefore, the area is 0.
-7m - 3m + 5m = -5m
what is 7m+7-5m
I think there is a missing operator in your question; I will guess you mean 5m + 7m - 3 = 33, because that has a nice round answer. First, add 3 to each side: 5m + 7m = 36 Then, simplify the left side: 12m = 36 Finally, divide both sides by 12: m = 3
The goat can graze a quarter circle of radius 7m (since the rope length is 7m) within the square plot of 12m. Hence the area it can graze can be given by /4. Therefore (3.14*7*7)/4=38.5sq.m
5m-7m = 12 -2m = 12 -2m/-2 = 12/-2 m = -6