-7m - 3m + 5m = -5m
what is 7m+7-5m
I think there is a missing operator in your question; I will guess you mean 5m + 7m - 3 = 33, because that has a nice round answer. First, add 3 to each side: 5m + 7m = 36 Then, simplify the left side: 12m = 36 Finally, divide both sides by 12: m = 3
The goat can graze a quarter circle of radius 7m (since the rope length is 7m) within the square plot of 12m. Hence the area it can graze can be given by /4. Therefore (3.14*7*7)/4=38.5sq.m
5m-7m = 12 -2m = 12 -2m/-2 = 12/-2 m = -6
Gather the m's and n's by rewriting it. 7m - 11n - n + 5m 7m + 5m -11n - n (7m + 5m) + (-11n - n) 12m - 12n ■
-7m - 3m + 5m = -5m
what is 7m+7-5m
I think there is a missing operator in your question; I will guess you mean 5m + 7m - 3 = 33, because that has a nice round answer. First, add 3 to each side: 5m + 7m = 36 Then, simplify the left side: 12m = 36 Finally, divide both sides by 12: m = 3
35m2
The goat can graze a quarter circle of radius 7m (since the rope length is 7m) within the square plot of 12m. Hence the area it can graze can be given by /4. Therefore (3.14*7*7)/4=38.5sq.m
5m-7m = 12 -2m = 12 -2m/-2 = 12/-2 m = -6
To find the area of a quadrilateral with sides of 7m, 4m, 5m, and 3m, you can use Brahmagupta's formula for the area of a cyclic quadrilateral: Area = √(s-a)(s-b)(s-c)(s-d), where s is the semiperimeter (s = (a + b + c + d) / 2) and a, b, c, and d are the lengths of the sides. Plug in the values of the sides into the formula to calculate the area.
Hcucugi
35 m2
A = 1/2bh 1/2 * 5 * 7 = 17.5m2
Just multiply 5m x 7m. The depth won't change the area of the top surface. Now, if you have a block and want to have its total surface area, calculate the area of the six bounding rectangles, and add them: two times 5x7, two times 5x1.6, two times 7x1.6.