1) When a quantity (variable n) in an equation is not know and you are trying to evaluate it. For example, if a banana costs 5 cents, how many can you buy for 25 cents. We solve this by saying Let n be the number of bananas that we can buy for 25 cents, then we have 5 x n = 25 and hence n = (25/5) = 5 2) When you want to express the general term in a series. For example the arithmetic series 1, 4, 7, 10, 13, 16,.......... is really 1, (1+3), (1+6), (1+9), (1+12), (1+15).......... and in general for such an arithmetic series you can find the 100th, 223rd, 567th term without writing down the long chain of numbers. How? we see a pattern in the arithmetic series. If we represent the starting number (1 in our case) as "a"and the equal increment from one term to the next (that's how an aritmetic series is defined) as "r" then the formlua "a + (n-1)r" gives you the n-th number. Remember that in the illustration above 1 is considered the 1st term in the series, (1+3) is the2nd term, (1+6) is the3rd term and so on.
I don't know that you can do it just by looking at one. (At least, I'm not clever enough with arithmetic to do that.) But it's possible to do it using some simple aritmetic. Here's an input-output table.5 386 457 528 59The first thing I notice is that the numbers in the left-hand column are evenly spaced; the difference between any two of them is just one. The differences between all of the numbers in the right-hand column are also all the same, seven. So this input-output table represents a linear function.In case you're working in a slightly more advanced situation here's another example:3 117 239 2913 41In this case the left-hand column numbers are not evenly spaced and I can't just look at the differences between the numbers on the left. However, there's a slightly more advanced technique that I can apply.( 23 - 11 ) / ( 7 - 3 ) = 12 / 4 = 3( 29 - 23 ) / ( 9 - 7 ) = 6 / 2 = 3( 41 - 29 ) / ( 13 - 9 ) = 12 / 4 = 3The three slopes are the same. Therefore, the input-output table represents a linear function.
The 12th odd number.
William Rickard has written: 'The miner's manual of aritmetic and surveying..'
An arithmetic sequence is an ordered set of numbers such that the difference between any two successive members of the set is a constant.
"The Devil's Arithmetic" is a story and film about the holocaust. The title refers to the fact that each day another person is brought to the gas chamber is another day the others can live.
They had Aritmetic. (English) They had Decimation. (Maths) Art
To find the sum of the first 48 terms of an arithmetic sequence, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum of the first n terms, a1 is the first term, and an is the nth term. In this case, a1 = 2, n = 48, and an = 2 + (48-1)*2 = 96. Plugging these values into the formula, we get: S48 = 48/2 * (2 + 96) = 24 * 98 = 2352. Therefore, the sum of the first 48 terms of the given arithmetic sequence is 2352.
1) When a quantity (variable n) in an equation is not know and you are trying to evaluate it. For example, if a banana costs 5 cents, how many can you buy for 25 cents. We solve this by saying Let n be the number of bananas that we can buy for 25 cents, then we have 5 x n = 25 and hence n = (25/5) = 5 2) When you want to express the general term in a series. For example the arithmetic series 1, 4, 7, 10, 13, 16,.......... is really 1, (1+3), (1+6), (1+9), (1+12), (1+15).......... and in general for such an arithmetic series you can find the 100th, 223rd, 567th term without writing down the long chain of numbers. How? we see a pattern in the arithmetic series. If we represent the starting number (1 in our case) as "a"and the equal increment from one term to the next (that's how an aritmetic series is defined) as "r" then the formlua "a + (n-1)r" gives you the n-th number. Remember that in the illustration above 1 is considered the 1st term in the series, (1+3) is the2nd term, (1+6) is the3rd term and so on.
CPU ,memory,hard disk, display,mailboardThe above is partially correct. The question is actually 40+ years old and was asked of me in an engineering class back in 1968. Back then it was 'What are the 5 parts of a computer.'Technically s computer does NOT need storage, aka a hard drive or a floppy etc to be a computer. It also doesn't need a display nor a mailboard. How mailboard got here I don't know.It needs:CPU (for processing commands)Input (from a keyboard, or a floppy, a hard drive etc to input both commands and data)Output ( to a monitor, a printer, magnetic tape, paper tape, punch cards etc)Memory ( the place an actual program and or data that the CPU uses MUST reside)The 5th item I alluded to is the Arithmetic Processor. The CPU proocesses the commands while the Arithmetic Processor manipulates the data to add, subtract, multiply and divide. In today's computers (post-1985) the CPU and the Arithmetic Processor are on the same chip. Previously, for those who remember the Z80 and the 8080 processors, for more "computing power" you could install an Aritmetic Processor to upgrade the PC and give the built-in arithemtic processor more capability.
I don't know that you can do it just by looking at one. (At least, I'm not clever enough with arithmetic to do that.) But it's possible to do it using some simple aritmetic. Here's an input-output table.5 386 457 528 59The first thing I notice is that the numbers in the left-hand column are evenly spaced; the difference between any two of them is just one. The differences between all of the numbers in the right-hand column are also all the same, seven. So this input-output table represents a linear function.In case you're working in a slightly more advanced situation here's another example:3 117 239 2913 41In this case the left-hand column numbers are not evenly spaced and I can't just look at the differences between the numbers on the left. However, there's a slightly more advanced technique that I can apply.( 23 - 11 ) / ( 7 - 3 ) = 12 / 4 = 3( 29 - 23 ) / ( 9 - 7 ) = 6 / 2 = 3( 41 - 29 ) / ( 13 - 9 ) = 12 / 4 = 3The three slopes are the same. Therefore, the input-output table represents a linear function.
What most people generally consider a "computer" consists of several things: the outsides or peripherals (monitor, mouse, keyboard etc), and the insides or components (power supply, graphics card, motherboard, memory, hard drive, floppy drive, CD drive). While it is possible to have a computer without one or more of these items, most computers have these, as well as others The above is a VERY good answer because Rashean29 is smart enough to know that many 'extra' items are not needed for a computer to be a true computer. The question is actually 40+ years old and was asked of me in an engineering class back in 1968. Back then it was 'What are the 5 parts of a computer.'Technically s computer does NOT need storage, aka a hard drive or a floppy etc to be a computer. It also only needs 1 input device and 1 output device to be 'functional.' Most computers today have multiples in each of those categories.It needs:CPU (for processing commands)Input (from a keyboard, or a floppy, a hard drive etc to input both commands and data)Output ( to a monitor, a printer, magnetic tape, paper tape, punch cards etc)Memory ( the place an actual program and or data that the CPU uses MUST reside)The 5th item I alluded to is the Arithmetic Processor. The CPU proocesses the commands while the Arithmetic Processor manipulates the data to add, subtract, multiply and divide. In today's computers (post-1985) the CPU and the Arithmetic Processor are on the same chip. Previously, for those who remember the Z80 and the 8080 processors, for more "computing power" you could install an Aritmetic Processor to upgrade the PC and give the built-in arithemtic processor more capability.
Input storage processing output The above is almost correct. Actually, it's the closest I've seen to the correct answer. The question is actually 40+ years old and was asked of me in an engineering class back in 1968. Back then it was 'What are the 5 parts of a computer.' Storage is too vague. The answer here is memory. Technically s computer does NOT need storage, aka a hard drive or a floppy etc to be a computer. It needs: CPU (for processing commands) Input (from a keyboard, or a floppy, a hard drive etc to input both commands and data) Output ( to a monitor, a printer, magnetic tape, paper tape, punch cards etc) Memory ( the place an actual program and or data that the CPU uses MUST reside) The 5th item I alluded to is the Arithmetic Processor. The CPU proocesses the commands while the Arithmetic Processor manipulates the data to add, subtract, multiply and divide. In today's computers (post-1985) the CPU and the Arithmetic Processor are on the same chip. Previously, for those who remember the Z80 and the 8080 processors, for more "computing power" you could install an Aritmetic Processor to upgrade the PC and give the built-in arithemtic processor more capability.