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depends, but usually girls with long legs but they have to be fit as well
There are no legs on the bus, it has wheels.-------------------------------------------------------Quite correct but in the bus there were :-Bus driver = 2 legs7 Girls = 14 legs98 Cats = 292 legs= 308 legs in total.(PS I am not counting any legs belonging to the seats that the driver and girls were sitting on) ______________________________________ If you want to count it that way there 7 girls and each has 7 bags that is 49 bags in total, each bag contains 7 cats (each with 7 kittens) so there are 56 cats & kittens per bag. Making a total of 2744 cats and kittens (49 bags x 56 felines), each has 4 legs, giving a total of 10,976 feline legs. Then add the 14 legs from the girls, plus a possible bus driver (2 legs) and perhaps a conductor, with 2 more legs (as it appears to be a school bus) would give a total of 10,994 legs but the bus still has wheels.
The answer to this commonly-posed riddle is that buses don't have legs, they have wheels. Therefore, the bus has no legs.
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The riddle answer is that there are no legs on a bus, just wheels. The meth answer is complicated by the fact that it does not mention the "bus driver" who resumably has 2 good legs.MathThe total number of (girl) legs is 10, and the total number of cat legs is (125 cats + 625 kittens) x 4 = 3000 kitty legs. So not counting the bus driver, there are 3010. Counting the bus driver, there are originally 3012 legs.If 3 girls get off with their backpacks, the number falls to 1204 or 1206 with the driver.---5 girls = 10 legs25 baskets125 cats = 500 legs625 kittens = 2500 legs3010 legs in allNo. of legs per girl1 girl = 2 legs5 baskets25 cats = 100 legs125 kittens = 500 legs602 legs per girlWith the proper data given, the formula would be: (let N=no. of legs left after the 3 girls got off the bus, A=all the legs in the bus, G=no. of legs per girl)N = A - 3(G)N = 3010 - 3(602)N = 3010 - 1806N = 1204 legsThus, 1204 legs are in the bus (1206 legs if the driver is included),