One plus cosecant squared x is equal to cotangent squared x.
secant of (A) = cosecant of (90- A) 'A' here is 80 degrees.
No.
The formula for "Take off" 45degrees elbow: 1.) For Metric: N.P.S. x 5/8 2.) For Imperial: N.P.S. x .625 Formula for travel of 45 degrees: Run x Cosecant 45degrees = Run x 1.4142 =
They are: 90 degrees, 45 degrees and 45 degrees
One plus cosecant squared x is equal to cotangent squared x.
1 + cot2x = csc2x
The cosecant of an angle is the reciprocal of the sine of that angle. So, to find the cosecant of 105 degrees, you first need to find the sine of 105 degrees. The sine of 105 degrees is approximately 0.9659. Therefore, the cosecant of 105 degrees is approximately 1.0353 (1 divided by 0.9659).
secant of (A) = cosecant of (90- A) 'A' here is 80 degrees.
1.624
No.
Approx 2.6131
Cosecant(115 deg) = 1/sine(115 deg) = 1/0.9063 = 1.1034
Hypotenuse = sqrt(side1 squared + side2 squared) and since the angles (other than the 90 degrees) are 45 degrees each, the side1 and side2 are equal, so Hypotenuse = sqrt((2 x side1) squared) = sqrt(4 x side1 squared) which is 2 x sqrt(side1 squared)
yes 1 + cot x^2 = csc x^2
Assuming that "secany" is meant to be secant, the answer is cosecant.
The formula for "Take off" 45degrees elbow: 1.) For Metric: N.P.S. x 5/8 2.) For Imperial: N.P.S. x .625 Formula for travel of 45 degrees: Run x Cosecant 45degrees = Run x 1.4142 =