it is something that is timesed by the type of water added to the weight of the the person breathing on it. In the end it is just a load of banta and lollz
Volume = cross sectional area * lengthArea = 2* cross sectional area + perimeter of cross section * length
If the diameter doubles (x2), the cross-sectional area quadruples (x4).
Other things being equal, more cross-sectional area will cause less resistance.
The wire with the greatest cross-sectional area is typically a thick copper wire, such as that used in electrical applications, measured in American Wire Gauge (AWG). For example, a 0000 AWG (4/0) wire has a cross-sectional area of approximately 53.5 mm². In general, as the AWG number decreases, the wire diameter and cross-sectional area increase. Thus, the thickest wire in standard gauge systems will have the greatest cross-sectional area.
9 AWG
Cross Sectional Area = Width x Average Depth
The cross-sectional area of a river is the total area that the river occupies when viewed from above. It is the area between the two banks of the river and includes the width and depth of the water. This measurement is important for calculating the volume of water flow in the river.
It is the area of the plane (the surface) covered by the water in the river channel. It is the product of the width of the channel, and the average depth of the river
You cannot create a cross sectional area of a rectangle. You can only create cross sectional areas for triangular shapes.
the larger the cross sectional area, the smaller the resistance
measure the channel height and then width and multiply them together
Volume = cross sectional area * lengthArea = 2* cross sectional area + perimeter of cross section * length
A Y12 bar typically has a cross-sectional area of 113 square millimeters.
reduction ratio= initial cross sectional area/final cross sectional area
cross-sectional area = 0.5*(sum of parallel sides)*height
The relationship between resistance and cross-sectional area in a conductor is inversely proportional. This means that as the cross-sectional area of a conductor increases, the resistance decreases, and vice versa. This relationship is described by the formula: Resistance (resistivity x length) / cross-sectional area.
cross sectional area of cable * voltage drop