It is: 3.1*3.1*3.1 = 29.791
3.141380652
The length increases by a 3√3 or 31/3 = 1.4422 (approx).
It is: 27 because 3*3*3 = 27
Somehow I messed up andused 31 instead of 35 That is why you are receiving an improvement Do a Google search for Diagonal of a cube Find this website. mathcentral.uregina.ca/QQ/database/QQ.09.04/brett1.HTML - Draw a cube You will see how to find the diagonal of a cube. You use Pythagorean Theorem Draw a cube Label each side as s Draw the diagonal of the base of the cube Diagonal of base = (s^2 + s^2 )^0.5 Let the diagonal of the base be the horizontal side of the right triangle whose hypotenuse is the diagonal of the cube. The height of the cube is the vertical side of the right triangle whose hypotenuse is the diagonal of the cube. Now determine the length of the diagonal of the cube. (diagonal of base)^2 + (height of cube)^2 = (diagonal of cube )^2 Diagonal of base = (s^2 + s^2 )^0.5….Height of cube = s Use Pythagorean Theorem (diagonal of cube )^2 = (diagonal of base)^2 + (height of cube)^2 (diagonal of base)^2 = [(s^2 + s^2 )^0.5]^2 = s^2 + s^2 height of cube)^2 = s^2 (diagonal of cube)^2 = (s^2 + s^2 + s^2) (diagonal of cube )^2 = (3 * s^2) diagonal of cube = (3 * s^2)^0.5 = 35 (3 * s^2)^0.5 = 35 Square both sides 3s^2 = 31^2 = 1225 s^2 = 408.33 s = 40833^0.5 s = 20.2 cm
volume is to a cube volume is to a cube
3.141380652
014472089
961 and 29,791.
no
The length increases by a 3√3 or 31/3 = 1.4422 (approx).
Some items that weigh approximate to 31 grams of gold include a grown-up honeybee, a sugar cube, or a typical AAA battery.
It is: 27 because 3*3*3 = 27
5 and 8
That's tough to say. A meter is longer than a yard, so Maya's is bigger, but Angela's is prettier.
Somehow I messed up andused 31 instead of 35 That is why you are receiving an improvement Do a Google search for Diagonal of a cube Find this website. mathcentral.uregina.ca/QQ/database/QQ.09.04/brett1.HTML - Draw a cube You will see how to find the diagonal of a cube. You use Pythagorean Theorem Draw a cube Label each side as s Draw the diagonal of the base of the cube Diagonal of base = (s^2 + s^2 )^0.5 Let the diagonal of the base be the horizontal side of the right triangle whose hypotenuse is the diagonal of the cube. The height of the cube is the vertical side of the right triangle whose hypotenuse is the diagonal of the cube. Now determine the length of the diagonal of the cube. (diagonal of base)^2 + (height of cube)^2 = (diagonal of cube )^2 Diagonal of base = (s^2 + s^2 )^0.5….Height of cube = s Use Pythagorean Theorem (diagonal of cube )^2 = (diagonal of base)^2 + (height of cube)^2 (diagonal of base)^2 = [(s^2 + s^2 )^0.5]^2 = s^2 + s^2 height of cube)^2 = s^2 (diagonal of cube)^2 = (s^2 + s^2 + s^2) (diagonal of cube )^2 = (3 * s^2) diagonal of cube = (3 * s^2)^0.5 = 35 (3 * s^2)^0.5 = 35 Square both sides 3s^2 = 31^2 = 1225 s^2 = 408.33 s = 40833^0.5 s = 20.2 cm
If by cube you mean perfect cube (a cube of an integer), then no, and the nearest perfect cube is 81.
A cube. A cube. A cube. A cube.