To find the solution, we first need to calculate the difference between 6 and 8, which is -2. Then, we subtract this difference from d. Therefore, the expression "d decreased by the difference of 6 and 8" can be written as d - (-2), which simplifies to d + 2.
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The UNION of two sets is the set of elements which are in either set. For example: let C = (4, 5, 6) and let D = (6, 7, 8). Now the UNION of C and D, written C D = (4, 5, 6, 7, 8). There is no need to list the 6 twice. The INTERSECTION of two sets is the set of elements which are in both sets. For example: let C = (4, 5, 6) and D = (6, 7, 8). The INTERSECTION of C and D, written C D = (6).
I am assuming this is an arithmetic series. Use the formula nth term = a + (n-1)d where a is the 1st term, and d is the difference between each term. 10th term = 8 + (10-1)d ==>8 +9d=53 ==> 9d = 53-8 = 45 ==> d = 5 The difference is 5.
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-6
8