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If we are using base 8 then 127 = (7 * 80) + (2 * 81) + (1 * 82) = 7 + 16 + 64 = 87 [i.e. (7 * 100) + (8 * 101)] in the decimal (base 10) system. In binary (base 2) we would write this as:

1010111.

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Q: What is decimal and binary equivalent of an octal number 127?
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