Logarithmic equation
what is the equation
The equation is "What = ?"
If this value a satisfy the equation, then a is a solution for that equation. ( or we can say that for the value a the equation is true)
"Figure out this mathematical equation" "This is how to figure out an equation" "An equation is something widely used in mathematics."
deltaG = deltaH -TdeltaS. deltaG = 0 at equilibrium. Therefore deltaH = TdeltaS
NaBH4 + 2H2O -> NaBO2 + 4H2 [1] DeltaG(298K)= -299 kJ/mol BH4 DeltaH(298K)= -231 kJ/mol BH4 (10.8 mass% H) NaBH4 + 4H2O -> NaB(OH)4 + 4H2 [2] DeltaG (298K)= -315 kJ/mol BH4 DeltaH = -247 kJ/mol BH4 (7.28 mass% H) NaBH4 + 6H2O -> NaB(OH)4.2H2O [3] DeltaG = -319kJ/mol BH4 DeltaH = -213 kJ/mol BH4 (5.48 mass% H) *Hydrolysis in Eq.[1] is not the most favorable reaction!
DeltaG = DeltaH - TDeltaS dG = -54.32 kJ/mol - (54'32+273)K(-354.2J/molK) NB Thevtemperature is quoted in Kelvin(K) and the Entropy must be converted to kJ by dividing by '1000'/ Hence dG = - 54.32kJ/mol - (327.32K)(-0.3542 kJ/molK) NB The 'K' cancels out. Then maker the multiplication dG = -54/32 kJ/mol - - 115.94 kJ/mol Note the double minus; it becomes plus(+). Hence dG = -54.32kj/mol + 115.94 kJ/mol dG = (+)61.61 kJ/mol Since dG is positive, the reaction is NOT thermodynamically feasible.
The enthalpy of formation (deltaHf) is the enthalpy change when 1 mole of a compound is formed from its constituent elements in their standard states. The deltaH of a reaction is the difference in enthalpy between the products and the reactants. The deltaH of a reaction can be calculated by taking the sum of the deltaHf of the products minus the sum of the deltaHf of the reactants.
the reaction is exothermic
-830
A thermochemical equation shows the amount of heat given out or taken in when the reaction occurs. CH4 + 2O2 = CO2 +2H2O, deltaH = -890 kJ/mol Note delta H is negative when heat is given out, exothermic and +ve when endothermic. Sorry can't do delta symbol - its a triangle!
•deltaG = nFE • •Pt + In3+ > In + Pt2+ •Pt > Pt2+ + 2e- •In3+ +3e- > In
Dry ice evaporating is endothermic-->+DeltaH A sparkler burning is exothermic--->-DeltaH The reaction that occurs in a chemical cold pack often used to ice athletic injuries is endothermic--->+DeltaH
The Nernst equation is E = ((-2.3RT)/zF)*(log10 [Ci/Co])E = equilibrium potential (mV)z = charge on the ion(2.3RT)/F = constant (60mV at 37C)Ci = intracellular concentrationCo = extracellular concentrationThe Nernst equation is important because it shows what the equilibrium potential would be for one ion.E.g. The resting membrane potential is normally ~70mV. So during an action potential Na channels open their gates briefly and Na rush inside the cell. Na is ionized and carries a positive charge. So when Na rushes into the cell it makes the inside of the cell more positive. If you were to break off the gate and allow Na to move freely back and forth, the Nernst equation shows us that the equilibrium point for Na is ~+65mV.•deltaG - DG0 = R T ln Q• deltaG = nFE••••E = E0+ (RT / nF) ln Q
A thermochemical equation shows the amount of heat given out or taken in when the reaction occurs. CH4 + 2O2 = CO2 +2H2O, deltaH = -890 kJ/mol Note delta H is negative when heat is given out, exothermic and +ve when endothermic. Sorry can't do delta symbol - its a triangle!
It is endothermic. The heat of the water in the calorimeter decreases (giving you a -deltaH), which means that the system absorbed heat, making the reaction endothermic.