x - y = xy
differentiating wrt x
1 - (dy/dx) = x(dy/dx) + y
(x + 1)(dy/dx) + y + 1 = 0
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no. its an exponential with a vertical zero axis
dy/dx = 2cos2x
The differential of the product xy with respect to x is y + x dy/dx. The differential of logy with respect to x is (1/y) dy/dx. The role of c in this question is not made clear.
To find the xy-trace, set z = 0 in the equation -5x - 2y - 3z = 10. Simplifying, we get -5x - 2y = 10. This is the equation of the xy-trace for the given plane.
5x 2y = 10