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The differential of the product xy with respect to x is y + x dy/dx. The differential of logy with respect to x is (1/y) dy/dx. The role of c in this question is not made clear.

Q: How do you differentiate xy equals logy c?

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Inverse proportion implies xy = c where c is the constant of [inverse] proportionality. x = 2 and y = 36 implies xy = 72 = c So the relationship is xy = 72 Then, if x = 4, y = 72/x = 72/4 = 18

y' = (sec(x))^2

The variable c times the variable b simply equals cb. Just as the variable x times the variable y would equal xy, and so on.

by transitive property

The answer depends on what R and C are.

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Inverse proportion implies xy = c where c is the constant of [inverse] proportionality. x = 2 and y = 36 implies xy = 72 = c So the relationship is xy = 72 Then, if x = 4, y = 72/x = 72/4 = 18

y' = (sec(x))^2

The variable c times the variable b simply equals cb. Just as the variable x times the variable y would equal xy, and so on.

In general, yes. However, if there is a drawing that goes along with this question, and it shows more information about 'c' that you have not bothered to share, then it's certainly possible that point 'c' may not lie in the same plane as 'xy'.

by transitive property

a= (+a) or a= (-) b= 2a b= 2a c= (-a) c= (+a)

A.

2a. (a, b and c are all equal.)

Turbo C compiles c source. turbo c++ compiles c++ source code.

c

Yes.

The answer depends on what R and C are.