That's a peculiar question. I'd call that the 'effective average speed',
or the 'apparent average speed'.
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displacement+time divided by distance
(Angular displacement divided by 360 degrees or pi radians)/(Time measured in minutes)
The magnitude of displacement is equal to distance traveled when motion is in a straight line.
Displacement over time is velocity - distance over time is speed.The reason is that:Displacement is a vector quantity (has a direction as well as a magnitude), whereas speed is a scalar quantity (has no direction, only magnitude).
Velocity is displacement divided by time. Displacement is different from distance traveled, as displacement states how far you traveled in RELATION to a starting point. The formula for Velocity is ---- v = x / t v = Velocity x = Displacement t = Time velocity is a vector quantity so the direction should also be specified unless it is implicit in the problem. ----