That's a peculiar question. I'd call that the 'effective average speed',
or the 'apparent average speed'.
displacement+time divided by distance
(Angular displacement divided by 360 degrees or pi radians)/(Time measured in minutes)
Displacement over time is velocity - distance over time is speed.The reason is that:Displacement is a vector quantity (has a direction as well as a magnitude), whereas speed is a scalar quantity (has no direction, only magnitude).
The magnitude of displacement is equal to distance traveled when motion is in a straight line.
Velocity is displacement divided by time. Displacement is different from distance traveled, as displacement states how far you traveled in RELATION to a starting point. The formula for Velocity is ---- v = x / t v = Velocity x = Displacement t = Time velocity is a vector quantity so the direction should also be specified unless it is implicit in the problem. ----
Displacement divided by time will give you the motion of an object that has no unbalanced force acting on it
Ifk
no
displacement+time divided by distance
Speed Average speed- the total distance traveled divided by the time it takes to travel that distance Velocity is also the distance or displacement divided by the time
Average speed is equal to the total distance travelled divided by total time.
Every time the unicycle returns to its starting point, the average velocity equals zero. C. The total displacement divided by the time.
when the body in motion covers equal displacement in equal intervals of time.
(Angular displacement divided by 360 degrees or pi radians)/(Time measured in minutes)
yes, the average speed equals distance divided by time
Displacement over time is velocity - distance over time is speed.The reason is that:Displacement is a vector quantity (has a direction as well as a magnitude), whereas speed is a scalar quantity (has no direction, only magnitude).
displacement is equal to the distance you traveled when the object is moving at shortest path