All multiples of 56, which is an infinite number.
Two is divisible by 56, but the number does not come out evenly. You get 0.0357 as your answer. 56 is divisible by 2 and it goes in evenly, however. (56/2 is 28).
56 is divisible by: 1, 2, 4, 7, 8, 14, 28, 56.
56
5+6=11 which is not divisible by 3, then 56 is not divisible by 3
No, 56/9 = 6.22222(recurring)
Two is divisible by 56, but the number does not come out evenly. You get 0.0357 as your answer. 56 is divisible by 2 and it goes in evenly, however. (56/2 is 28).
56 is divisible by 1, 2, 4, 7, 8, 14, 28, and 56.
56 is divisible by: 1, 2, 4, 7, 8, 14, 28, 56.
56
5+6=11 which is not divisible by 3, then 56 is not divisible by 3
No, 56/9 = 6.22222(recurring)
To show that the product of 56 and 39 is exactly divisible by 21, you can check if both numbers are divisible by the prime factors of 21, which are 3 and 7. Since 56 is divisible by 7 (56 ÷ 7 = 8) and 39 is divisible by 3 (39 ÷ 3 = 13), their product will also be divisible by both 3 and 7. Therefore, 56 x 39 is divisible by 21.
7
No.
No - 56/45 = 1.24 recurring (that is, 1.24444..).
No. 100 is not evenly divisible by 56.
14 x 4 = 56