56 is divisible by: 1, 2, 4, 7, 8, 14, 28, 56.
The numbers that are divisible by 28 are infinite. The first four are: 28, 56, 84, 112 . . .
1x56 2x56 3x56 etc.
Two is divisible by 56, but the number does not come out evenly. You get 0.0357 as your answer. 56 is divisible by 2 and it goes in evenly, however. (56/2 is 28).
No number between 20 and 40 is divisible by all 4 numbers. The smallest number divisible by all 4 of those numbers is: 56
56 of them.
The numbers that are divisible by 56 are in the form 56k where k is the integer constant.
The numbers that are divisible by 28 are infinite. The first four are: 28, 56, 84, 112 . . .
8, 7, 2, 28
1x56 2x56 3x56 etc.
224 is evenly divisible by these numbers: 1, 2, 4, 7, 8, 14, 16, 28, 32, 56, 112 and 224.
Two is divisible by 56, but the number does not come out evenly. You get 0.0357 as your answer. 56 is divisible by 2 and it goes in evenly, however. (56/2 is 28).
No number between 20 and 40 is divisible by all 4 numbers. The smallest number divisible by all 4 of those numbers is: 56
28, 56, 84, and all other multiples of 28 that are factors of other numbers are also divisible by 28.
56 of them.
c.
They are: 50 52 54 56 58 and 60
Well, honey, let me break it down for you. 56 is divisible by 2 because it's even, by 4 because the last two digits form a number divisible by 4, and by 8 because the last three digits form a number divisible by 8. However, it's not divisible by 3, 5, 6, or 9. So, to answer your question, 56 is not divisible by each of those numbers.