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limit x tends to infinitive ((e^x)-1)/(x)
maths signs
e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.
if you take your time youll figure out its e=mc2
x[x+1] squared Simplified is, to my knowledge, x squared plus ( x + 1) squared