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Q: What is example of partial dependency?
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An example of global dependency on a product?

condems


What is Partial function?

Partial Functional Dependency Indicates that if A and B are attributes of a table , B is partially dependent on A if there is some attribute that can be removed from A and yet the dependency still holds. Say for Ex, consider the following functional dependency that exists in the Tbl_Staff table: StaffID,Name -------> BranchID BranchID is functionally dependent on a subset of A (StaffID,Name), namely StaffID. Source :http://www.mahipalreddy.com/dbdesign/dbqa.htm


What is difference between Partial Functional Dependency and Full Functional Dependency?

A functional dependency is defined as a constraint between two sets of attributes in a relation from a database.Given a relation R, a set of attributes X in R is said to functionally determine another attribute Y, also in R, (written X→ Y) if and only if eachX value is associated with at most oneY value.A functional dependency X --> Y is full functional dependency if removal of any attribute 'k' from X means that the dependency does not hold any more. Full functional dependency is minimal in size.Partial Functional Dependency Indicates that if A and B are attributes of a table, B is partially dependent on A if there is some attribute that can be removed from A and yet the dependency still holds.A key is a set of attributes that uniquely identifies an entire tuple, a function dependency allow us to express constraints that uniquely identify the values of certain attribute.


How do you do partial quotients for division for fifth grade?

to do this is that you do the simple steps for example divide mulitiply subtract bring down


Meaning of partial quotients?

If you have a ratio of polynomials in which the denominator can be factorised, then partial quotients or partial fractions are form an equivalent expression but one in which the denominators of the terms are those fractions.For example, suppose you start with (2x + 5)/(x^2 + 3x + 2)The denominator can be factorised into (x + 1)*(x + 2)So the partial fractions are 3/(x + 1) - 1/((x + 2).