The formula for finding the diagonals of any polygon is: 0.5*(n2-3n) where n = the number of sides. A trapezoid has 4 sides so: 0.5*(16-12) = 2 diagonals
It has 170 diagonals by using the diagonal formula
Because in both cases their diagonals cross at right angles So their areas are: 0.5*product of diagonals
Using the formula: 0.5*(n2-3n) it has 54 diagonals
Using the formula: 0.5*(142-42) = 77 diagonals
The formula for finding the amount of diagonals in a polygon is n(n-3)/2. So 14(14-3)/2 = 77 Diagonals
The formula for finding the diagonals of any polygon is: 0.5*(n2-3n) where n = the number of sides. A trapezoid has 4 sides so: 0.5*(16-12) = 2 diagonals
By using the polygon diagonal formula or the quadratic equation formula in which in both formulae they work out that the polygon in question has 21 sides.
There are 560 diagonals by using the diagonal formula
It has 170 diagonals by using the diagonal formula
Because in both cases their diagonals cross at right angles So their areas are: 0.5*product of diagonals
It has 40 diagonals.Improved Answer:-Using the formula for diagonals of a polygon: 0.5*(442-132) = 902 diagonals
n side polygon has n(n-3)/2 diagonals therefore a hexagon has 9 diagonals
None because it does not comply with the formula 0.5*(n2-3n) = diagonals
Using the diagonal formula: 0.5*(182-54) = 135 diagonals
Using the formula: 0.5*(n2-3n) it has 54 diagonals
Using the formula: 0.5*(142-42) = 77 diagonals