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How many diagonals can you drawn from one vertex in a 35 sided polygon?
In a polygon with n sides, the number of diagonals that can be drawn from one vertex is given by the formula (n-3). Therefore, in a 35-sided polygon, you can draw (35-3) = 32 diagonals from one vertex.
How many diagonals in decagon?
There are 35 diagonals in a 10 sided decagon
How many diagonals in decagon have?
35
What polygon has 35 diagonals?
A decagon. Proof: In an n sided polygon, each vertex would be have (n-3) diagonals attached to it, as it would be connected to every vertex other than itself and the two next to it by a diagonal. There are n sides, so there are n(n-3) ends of diagonals. Therefore there are (n(n-3))/2 diagonals in the polygon. Taking the number of diagonals to be 35, we have: (n(n-3))/2 = 35 n(n-3) = 70 which gives the quadratic n2-3n-70 = 0 Solving this gives n = 10 and -7. -7 can be ignored, so the answer is 10.
A hexagon is a polygon with six sides and six what?
a hexagon has 35 diagonals. at my school we get merits and so everyone went home with the question "how many diagonals does a pentogan have so i went up to my teach an guessed 35 and she said it wuz right. ... i got a merit...i am a level 5 out of 5 student who IS 10!!!
