There are 560 diagonals by using the diagonal formula
if a polygon has 560 diagnose how many vertices does it have
A diagonal of a polygon is a segment drawn from one vertex to another non-adjacent vertex in a polygon. This leaves 32 diagonals that can be drawn from one vertex in a 35 sided polygon.
There are 35 diagonals in a 10 sided decagon
35
A decagon. Proof: In an n sided polygon, each vertex would be have (n-3) diagonals attached to it, as it would be connected to every vertex other than itself and the two next to it by a diagonal. There are n sides, so there are n(n-3) ends of diagonals. Therefore there are (n(n-3))/2 diagonals in the polygon. Taking the number of diagonals to be 35, we have: (n(n-3))/2 = 35 n(n-3) = 70 which gives the quadratic n2-3n-70 = 0 Solving this gives n = 10 and -7. -7 can be ignored, so the answer is 10.
It has 35 diagonals
(35*(35-3))/2 (35*32)/2 1120/2 560 diagonals
It will have ten sides
It has 10 sides because using the formula 0.5*(102-30) = 35 diagonals
if a polygon has 560 diagnose how many vertices does it have
A diagonal of a polygon is a segment drawn from one vertex to another non-adjacent vertex in a polygon. This leaves 32 diagonals that can be drawn from one vertex in a 35 sided polygon.
The number of diagonals is n(n-1)/2 - n substitute n=35 35(34)/2 - 35 = 560
100 diagonals * * * * * No, it is 0.5*10*(10-3) = 35
35 diagonals
It depends if the polygon is convex or concave but if it is a regular polygon it would have 560
35.
A diagonal line of a polygon is a line that joins any two vertices not already joined by a side. A polygon with n sides has n(n-3)/2 diagonals → a decagon has 10(10-3)/2 = 10 × 7 ÷ 2 = 35 diagonals