You would take the following steps for G = A / (1-R):G = A / (1-R)Multiply by (1-R):G * (1-R) = ADivide by G:(1-R) = A/G1-R = A/GSubtract 1:-R = (A/G) - 1Divide By -1:R = -((A/G) - 1)Check Work:Original Problem:A = 12; R = 5G = 12 / (1-5)G = -3Solving For R:R = -((12/-3)-1)R = 5Therefore, R= -((A/G)-1)
what do you mean by Ra and Rz values
Yes, because GB = GR - RB
if r=5z and 15z =3 then r=10y
It would appear that r = y
5 golden rings.
You would take the following steps for G = A / (1-R):G = A / (1-R)Multiply by (1-R):G * (1-R) = ADivide by G:(1-R) = A/G1-R = A/GSubtract 1:-R = (A/G) - 1Divide By -1:R = -((A/G) - 1)Check Work:Original Problem:A = 12; R = 5G = 12 / (1-5)G = -3Solving For R:R = -((12/-3)-1)R = 5Therefore, R= -((A/G)-1)
Find how many R's are in 1G (If you divide 4 by 1000 you get .004 per G) Multiply your answer by the G's (400) to get total R's. (.004R x 400G) I get an answer of 400G=1.6R
Fifth Day of Christmas = Golden Rings
what is Rz and Ra urface finish?
Approx - Rz is 4 times of Ra
the answer is r.
what do you mean by Ra and Rz values
Yes, because GB = GR - RB
N i g g e r s
if r=5z and 15z =3 then r=10y
It would appear that r = y