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What is the log prosedure?
I assume you are asking how to solve a logarithmic equation. Well let's quickly review what the log function is: for the equation log(x)=y, we are saying that 10^y=x. So once you have isolated the logarithm, take the value of the base, raise it to the nth power (when 'n' is the value that the function is equal to) and set that equal to the value inside of the log.
Why negative value is not valid for log?
The logarithm function is the inverse of the exponential function. Take the exponential function (base 10): y = 10x. The inverse of this is x = 10y. The function y = log(x) is used to define this inverse function. First look at y = 10x. Any real value of x will yield a positive real value for y. If x = 0, then y = 1; if x < 0 (negative) then y is between 0 and 1 (it will never equal zero, though). A value of 10-99999 is very close to zero, but not quite there. There are no real values of x which will give a negative y value for y = 10x. Now look at y = log(x) or x = 10y. No matter what real values for y, that we choose, x will always be a positive number, so a negative value of x in y = log(x) is not possible if you are limiting to real numbers. It is possible with complex and imaginary numbers to take a log of a negative number, or to get a negative answer to y = 10x.
Log of square root of y?
log of the square root of 'y' = 1/2 sqrt(y)
What is the definition of log?
log base m of x = y is equivalent to x=m^y
What is the difference between an anti-log and an exponential?
let x and y be two numbers ex = y log y = x antilog x = y
