y6
5x times the square root of y
2x square root 6x y squared
y2
Yes, if x and y = 1 √1 + √1 = √1 + 1 1 + 1 = 1 + 1 QED
square root (y) / Square root (3) root (y) / 1.73
x=y
y6
5x times the square root of y
If x is a multiplication symbol, then square root of 36(4)y^2 = square root of(4^2)(2^2)(y^2) = (4)(2)(y) = 8y If it is a variable x, then square root of 36x4y^2 = square root of (4^2)(x)(2^2)(y^2) = (4)(2)(y)(square root of x)= 8y(square root of x)
Oh, dude, the square root of x plus the square root of y is just that - the square root of x plus the square root of y. It's like adding apples and oranges, you can't really simplify it further. So, like, that's your answer, no need to overcomplicate things, man.
2x square root 6x y squared
Algebraically if we have a number 'x^2' Then its square is (x^2)^2 = x^4 For the square root of x^2 = +/-x
logx^3logx^2log14 is 3logx2logxlog14 this equals 6 log14 (logx)^2 So for example, if y=6log14(logx)^2 the log x = square root of (y/6(log14))
y2
Yes, if x and y = 1 √1 + √1 = √1 + 1 1 + 1 = 1 + 1 QED
The square root of a number x is one that, when multiplied by itself gives the value x. So if y * y = x then y is the square root of x. But, (-y)*(-y) also equals x. So -y is also a square root of x. Thus, given any positive number, x, there are two numbers, y and -y whose square is x. So both of them are square roots of x. One of y and -y must be greater than 0 and the other must be less than 0. The one that is less than 0 is the negative square root. As an example, 4 * 4 = 16 and (-4) * (-4) = 16 so both, 4 and -4 are square roots of 16. -4 is the negative square root while 4 is the positive square root (also called the principal square root).