65.5
8.02 days
262 / 2 is equal to 131.
Not plutonium, but iodine-131 !!The half life of 131I is 8,0197 days.
The answer is simple it is 8 days for iodine-131 but it depends on what isotope you are talking about
Iodine 131 has a half-life of 8.0197 days. Barium has no half-life. So no, Iodine-131 is not more stable than barium-137.
Iodine-131 has a half-life of approximately 8 days, which means it takes about that long for half of a given amount of iodine-131 to decay into its stable form, xenon-131. After about 40 days (five half-lives), it will have decayed to a level that is generally considered negligible. The decay process continues, but the rate slows significantly as it approaches stability.
The half life of Iodine-131 is 8.02 days, that means that say if you had 1 gram of 131I after approximately 8 days there would be only 0.5g left. The other half would have become Xenon-131. After 6 half lives (~48 days in your case) you would only have 1.6% of the original amount left.
After 32 days, approximately 5 milligrams of the 80-milligram sample of Iodine-131 would be left. Iodine-131 has a half-life of about 8 days, so after each 8-day period, half of the remaining sample will decay.
After 16.14 days, which is two half-lives of iodine-131 (since 16.14 days / 8.07 days = 2), the amount of iodine-131 remaining would be (200 , \text{g} \times \left(\frac{1}{2}\right)^2 = 50 , \text{g}). Therefore, the amount of iodine-131 that has decayed to xenon-131 would be (200 , \text{g} - 50 , \text{g} = 150 , \text{g}). Thus, after 16.14 days, there would be 150 grams of xenon-131 formed.
Never. As a simple exponential-decay problem, it can get as small as you want if you're willing to wait long enough, but it never reaches zero.
1/24 = 1/16
About 2 and a half hours.