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Answer this a piece of poster has a perimeter of 130 cm what are the dimensions of the poster if its length is 35 cm longer than its width?
Suppose the width is W cm Then the length, L = W + 35 cm And the perimeter is 2W + 2L = 2W + 2(W+35) = 4W + 70 4W + 70 = 130 so that 4W = 60 or W = 15 and then L = W + 35 = 50 So the poster is 15 cm by 50 cm
What is the area of a rectangular desk top that is w cm wide and twice as long as it is wide?
Width = w cmLength = 2w cmArea = (length) x (width) = (2w cm) x (w cm) = 2w2 cm2
The length of the rectangle is greater than its breadth by 2 cm if the length is increased by 4 cm and the breadth decreased by 3cm the area remain same find the length and breadth of the rectangle?
The width is 18 cm and the length is 20 cm. The new dimensions are 15 by 24. The formula used is if w=width, w (w + 2) = (w - 3) (w + 6).
The perimeter of a rectangle is 90 cm. If the length is one and one-half times the width Find the length and the width?
Suppose the length is L cm. Then the width, W, is 2L/3 cm. Perimeter = 2(L+W) = 2(L+2L/3) = 10L/3 = 90 cm So L = 27 cm and W = 2L/3 = 18 cm.
What is l times w?
cm squared
The length of a rectangle is fixed at 27 cm what widths will make the perimeter greater than 86cm?
Recall that the perimeter is: P=2*L+2*W If L=27 cm, find W such that P>86 cm P>86 cm 2*L+2*W>86 cm 54 cm+2*W>86 cm 2*W>32 cm W>16 cm So widths greater than 16 cm will make the perimeter greater than 16 cm.
The length of a rectangle is 2cm longer than its width if the perimeter of the rectangle is 40cm find the area?
To find the area of a rectangle, you need to know the length and width. Let's denote the width as x cm. Since the length is 2 cm longer than the width, the length would be x + 2 cm. The perimeter of a rectangle is the sum of all its sides, which in this case is 2(width + length). So, we have 2(x + x + 2) = 40 cm. Solving this equation gives x = 8 cm. Therefore, the width is 8 cm and the length is 10 cm. The area of the rectangle is width * length, which is 8 cm * 10 cm = 80 cm².
What is the value of w if A equals 184 cm2 and l equals 23 cm?
A = w*l so 184 = w*23 or w = 184/23 = 8 cm
Answer this a piece of poster has a perimeter of 130 cm what are the dimensions of the poster if its length is 35 cm longer than its width?
Suppose the width is W cm Then the length, L = W + 35 cm And the perimeter is 2W + 2L = 2W + 2(W+35) = 4W + 70 4W + 70 = 130 so that 4W = 60 or W = 15 and then L = W + 35 = 50 So the poster is 15 cm by 50 cm
The length of a rectangle is 6 cm greater than its width its area is 952 cm squared find its dimension?
W (w + 6) = 952 ie w2 + 6w - 952 = 0 ie (w + 34)(w - 28) = 0 The width is 28 cm and the length 34 cm.
Find the perimeter of a rectangle 12.5 cm long and 3.5 cm wide?
The perimeter of a rectangle is simply the sum of the length of all four sides. So, l + w + l + w, or 2(l + w).
What is the perimeter of a rectangle with a length of 15 centimeters and with of 10 centimeters?
The perimeter of a rectangle is calculated by adding up the lengths of all its sides. In this case, the length is 15 centimeters and the width is 10 centimeters. To find the perimeter, you would add up all four sides: 15 cm + 10 cm + 15 cm + 10 cm = 50 cm. Therefore, the perimeter of the rectangle is 50 centimeters.
What is the area of a rectangular desk top that is w cm wide and twice as long as it is wide?
Width = w cmLength = 2w cmArea = (length) x (width) = (2w cm) x (w cm) = 2w2 cm2
The length of the rectangle is greater than its breadth by 2 cm if the length is increased by 4 cm and the breadth decreased by 3cm the area remain same find the length and breadth of the rectangle?
The width is 18 cm and the length is 20 cm. The new dimensions are 15 by 24. The formula used is if w=width, w (w + 2) = (w - 3) (w + 6).
The length of a rectangle is 3 cm less than 4 times the width The perimeter is 114 cm Find the width?
Suppose width = W cm Then 4 times width = 4W cm So Length, L = 4W - 3 cm Perimeter = 2*(L+W) = 2*(4W-3 + W) = 2*(5W -3) = 10W - 6 = 114 So 10W = 114+6 = 120 cm and so W = 12 cm.
What do you use to measure the capacity of a school locker?
A tape measure to measure the height (h cm), depth (d cm) and width (w cm). Then capacity = h*d*w cm3 = h*d*w/1000 litres.
He volume of a rectangular prism is 2058 cubic cm The length of the prism is 3 times the width The height is twice the width Find the height of the prism?
Let the width be "w" cm Length = 3w cm Height = 2wcm Hence w x 3w x 2w = 2058 cubic cm 6(w-cubed) = 2058 w-cubed = 2058/6 = 343 w = cube root of 343 = 7 cm
