Suppose the width is W cm Then the length, L = W + 35 cm And the perimeter is 2W + 2L = 2W + 2(W+35) = 4W + 70 4W + 70 = 130 so that 4W = 60 or W = 15 and then L = W + 35 = 50 So the poster is 15 cm by 50 cm
Width = w cmLength = 2w cmArea = (length) x (width) = (2w cm) x (w cm) = 2w2 cm2
The width is 18 cm and the length is 20 cm. The new dimensions are 15 by 24. The formula used is if w=width, w (w + 2) = (w - 3) (w + 6).
Suppose the length is L cm. Then the width, W, is 2L/3 cm. Perimeter = 2(L+W) = 2(L+2L/3) = 10L/3 = 90 cm So L = 27 cm and W = 2L/3 = 18 cm.
cm squared
Recall that the perimeter is: P=2*L+2*W If L=27 cm, find W such that P>86 cm P>86 cm 2*L+2*W>86 cm 54 cm+2*W>86 cm 2*W>32 cm W>16 cm So widths greater than 16 cm will make the perimeter greater than 16 cm.
The rectangle is 99 cm2 in area. Here's how we got it. The rectangle has length (l) and width (w). A length and a length and a width and a width all added up equals 40 cm. And l is 2 cm longer than w, so l = w + 2. If we add w + 2 and w + 2 (the two lengths) and w and w, we get 40 cm. That's 4w + 4 cm = 40 cm. 4w = 36 cm, and w = 9 cm. The width is 9 cm, and the length is 2 cm more or 11 cm. The rectangle is 9 cm by 11 cm, and its area is 9 x 11 cm2, or 99 cm2.
A = w*l so 184 = w*23 or w = 184/23 = 8 cm
Suppose the width is W cm Then the length, L = W + 35 cm And the perimeter is 2W + 2L = 2W + 2(W+35) = 4W + 70 4W + 70 = 130 so that 4W = 60 or W = 15 and then L = W + 35 = 50 So the poster is 15 cm by 50 cm
W (w + 6) = 952 ie w2 + 6w - 952 = 0 ie (w + 34)(w - 28) = 0 The width is 28 cm and the length 34 cm.
The perimeter of a rectangle is simply the sum of the length of all four sides. So, l + w + l + w, or 2(l + w).
The perimeter of a rectangle is P = 2(l + w) where: l = length w = width Let: l = 15 cm w = 10 cm Then: P = 2(15 cm + 10 cm) = 2(25 cm) = 50 cm So the perimeter of a rectangle is 50 cm.
Width = w cmLength = 2w cmArea = (length) x (width) = (2w cm) x (w cm) = 2w2 cm2
The width is 18 cm and the length is 20 cm. The new dimensions are 15 by 24. The formula used is if w=width, w (w + 2) = (w - 3) (w + 6).
Suppose width = W cm Then 4 times width = 4W cm So Length, L = 4W - 3 cm Perimeter = 2*(L+W) = 2*(4W-3 + W) = 2*(5W -3) = 10W - 6 = 114 So 10W = 114+6 = 120 cm and so W = 12 cm.
A tape measure to measure the height (h cm), depth (d cm) and width (w cm). Then capacity = h*d*w cm3 = h*d*w/1000 litres.
Let the width be "w" cm Length = 3w cm Height = 2wcm Hence w x 3w x 2w = 2058 cubic cm 6(w-cubed) = 2058 w-cubed = 2058/6 = 343 w = cube root of 343 = 7 cm