-2
-2m + 7 = m - 2 +7 +2 = m +2m 9 = 3m 3m = 9 m = 9/3 = 3 to test: -2(3) + 7 = (3) - 2 -6 + 7 = 3 - 2 1 = 1
When m is 7, (6m + 3) is (42 + 3) = 45.(45)3 = 91,125
it is prime. it cannot factor out.
The answer to y m 3 2y plus 10 and m 4 5y plus 100 is m = -15, and y = 1/3.
-2
m = 15
m^4 x m^3 = m^7Using a numerical example, 2^4 x 2^3 = 16 x 8 = 128 = 2^7
-2m + 7 = m - 2 +7 +2 = m +2m 9 = 3m 3m = 9 m = 9/3 = 3 to test: -2(3) + 7 = (3) - 2 -6 + 7 = 3 - 2 1 = 1
2
When m is 7, (6m + 3) is (42 + 3) = 45.(45)3 = 91,125
m7/2
The equilibrium constant Keq is calculated using the concentrations of the products raised to the power of their stoichiometric coefficients divided by the concentrations of the reactants raised to the power of their stoichiometric coefficients. In this case, Keq = [NH3]^2 / ([N2] * [H2]^3) = (3)^2 / (1*2^3) = 9 / 8.
it is prime. it cannot factor out.
m2 + 8m - 65 = (m + 13) (m - 5)
That factors to 3(m - 4n)(6m - n)
3m+2=17 First, subtract 2 to get m on one side. 3m+2-2=17-2 3m=15 Divide by 3 to get m by itself. 3m/3=15/3 m=5 m equals 5.